In humans, the alleles for blood type are designated IA (A-type blood), IB (B-type blood) and i (O-type blood). What are expected frequencies of the phenotypes in the following matings? • Heterozygote A x Heterozygote B: •IA IB x IA I • IA IA. x IB IB • AB x O

In humans, the alleles for blood type are designated IA (A-type blood), IB (B-type blood) and i (O-type blood). What are expected frequencies of the phenotypes in the following matings? • Heterozygote A x Heterozygote B: •IA IB x IA I • IA IA. x IB IB • AB x O

Name: In humans, the alleles for blood type are designated IA (A-type blood)
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: In humans, the alleles for blood type are designated IA (A-type blood), IB (B-type blood) and i (O-type blood). What are expected frequencies of the phenotypes in the following matings?• Heterozygote A x Heterozygote B: •IA IB x IA I• IA IA. x IB IB•

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 2CT: Still referring to Problem 1, what will be the possible genotypes of offspring from the following...

See similar textbooks

Similar questions

In dogs, black fur (B) is dominant to brown fur (b). In a genetic cross of two dogs that are heterozygous for the color of their fur, what is the genotype and the phenotypic ratio of the offspring? A)F: Bb, Bb, bb; ratio 2;1B)F: BB, bb; ratio 1:1C)F: Bb, bb, bb; ratio 1:1D)F: BB, Bb, Bb, bb; ratio 3:1E) F: BB, Bb; no ratio
If one human parent is heterozygous for blood type A (IAi), and the second parent is heterozygous for blood type B (IBi), what are the expected phenotypic ratios in their children? a. 1/4 with blood type AB, 1/4 with blood type A, 1/4 with blood type B, and 1/4 with blood type O b. 1/4 with blood type A (IAi), 1/2 with blood type AB (IAIB), and 1/4 with blood type B (IBi) c. 1/2 with blood type AB (IAIB), and 1/2 with blood type O (ii) d. 1/2 with blood type A (IAi), and 1/2 with blood type B (IBi) e. 1/2 with blood type A (IAi), and 1/2 with blood type O (ii)
The human MN blood group is determined by alleles (M and N) for a single gene that code for two specific, codominant markers found on the surface of red blood cells.If two individuals with the MN blood type produce offspring, which phenotypic ratio of offspring would result?1.100% MN2.50% MM: 25% MN: 25% NN3.50% MN: 25% NN: 25% MM4.50% MM: 50% NN
In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown below. Number of progeny Mating Parental Phenotypes Spotted/orange Spotted/white Striped /orange Striped /white 1 spotted/orange x striped/orange 623 0 637 0 2 spotted/white x striped/orange 0 0 0 712 3 spotted/white x striped/orange 122 131 128 133 4 spotted/orange x striped/white 0 0 430 422 6a) Using the information in the table above, assign a letter to each allele (make sure each allele can be uniquely identified, using Uppercase and lowercase and use a unique letter for each trait). Circle whether each allele is dominant (D) or recessive (R) below
In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown below. Number of progeny Mating Parental Phenotypes Spotted/orange Spotted/white Striped /orange Striped /white 1 spotted/orange x striped/orange 623 0 637 0 2 spotted/white x striped/orange 0 0 0 712 3 spotted/white x striped/orange 122 131 128 133 4 spotted/orange x striped/white 0 0 430 422 striped= S(dominant) spotted=s (recessive) white= W(dominant) orange=w (recessive) What are the genotypes of each parent in each cross? If more than one genotype is possible, list the alternative possibilities. (Remember that each mating involves a separate set of parents, so the 4 matings involve 8 separate…
In cats, blood-type A results from an allele (IA) that is dominant over an allele (iB) that produces blood-type B. There is no O blood type. The blood types of male and female cats that were mated and the blood types of their kittens follow. Give the most likely genotypes for the parents of each litter. Male parent Female parent Kittens a. A B 4 with type A, 3 with type B b. B B 6 with type B c. B A 8 with type A d. A A 7 with type A, 2 with type B e. A A 10 with type A f. A B 4 with type A, 1 with type B
In rabbits the dominant allele B produces a black coat color and the recessive genotype bb produces a brown coat. Body fat color in rabbits is white if a dominant allele Y is present and yellow if the genotype is yy. Assume the mating between rabbits with the following genotypes : BBYY x bbyy produces BbYy Calculate the recombination frequency if the BbYy offspring are mated back to brown rabbits having yellow fat bbyy and the following ratio of phenotypes is observed: Coat color Fat color # Observed Black White 125 Black Yellow 75 Brown White 85 Brown Yellow 115
In a species of dog, plaid color is represented by P and purple by p, short -tailed is T and long-tailed is t. What are the genotypes of a male who is purple with a long tail, and a female who is homozygous dominant for both traits? Which answer below is true? PpTT & PPTT pptt & PPTT short-tailed purple & long tailed plaid male: purple w/ long tail & female: plaid w/ short tail
Female pig Emmy Lou (straight tail, white-haired) with the haplotype cH/Ch was mated to a curly-tailed black-haired male pig Wilhelm (ch/ch). Curly tails are due to the cc genotype and black hair is due to the hh genotype. From the choices shown below, which genotype would you expect to be the most frequent among their offspring? cH/ch cH/ch CH/ch CH/ch ch/ch ch/ch cc/hh cc/hh All genotypes are equally likely. All genotypes are equally likely.
The allele A is brown fur and the allele a is white fur. In a mating between a heterozygous male and a heterozygous female, what is probability that they will have an offspring with brown fur and what is the probability they will have an offspring with white fur?
Two alleles of gene C control hair color in horses: C¹and C². Horses homozygous for allele C¹ are red, heterozygotes are yellow, and C² homozygotes are cream. In the offspring of matings between heterozygotes, what phenotypic ratio is expected? A) 2 yellow: 1 red B) 3 red: 1 cream C) 1 red: 2 yellow: 1 cream D) all red E) 9 red: 3 yellow: 4 cream
In Andalusian fowls, black (BB) and white (bb) individuals are homozygous. When a homozygous black bird (BB) is crossed with a homozygous white (bb) bird offspring are all bluish-gray (Bb). Show the cross as well as the genotypes and phenotypes of the parental cross between two heterozygous parents. 1. P1: _________ x _________ 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %: