Question
Asked Oct 24, 2019
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In one experiment you reacted 45.7g of Aluminum with 182.8g of Iron (III) oxide to produce Aluminum Oxide and Elemental iron (not diatomic).

a. How many mols of Iron (III) oxide do you have?

b. Which is the limiting agent?

c. If you produced 5 grams of aluminum oxide, how many atoms of aluminum are in 5 grams?

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Expert Answer

Step 1

The molecules that present inside any substance can be determined by calculating the number of moles. These moles are then multiplied by the Avogadro’s number to get the molecules present in the substance.

Step 2

Given data:

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Mass of aluminum (Al) = 45.7 g Mass of iron (II oxide (Fe,O,) -182.8 g Mass of aluminum oxide(Al,0,) =5 g

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Step 3

Part (a)

The number of moles of iron (III) oxide (Fe2O3) is ca...

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MassFeO Molar masseO Number of moles of Fe2O Molar mass of Fe,O; = 159.69 g mol1 Mass of Fe,O, 182.8g 182.8 g Number of moles of Fe,O 159.69 g mol =1.144 mol

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Inorganic Chemistry

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