In order to reduce the wait times and improve the facilities, a large walk-in clinicmanagement randomly selected 15 patients, and collected the data on their wait timein minutes (time between a patient registered at the main desk and was seen by adoctor). Considering a normal model for sample mean, the 95% confidence intervalfor the mean wait time (u) at this clinic based on this sample was (34 minutes, 87minutes).(i)Obtain the sample mean and sample standard deviation.(i)Obtain a 99% confidence interval for mean wait time. What is the marginof error?(i)the same confidence as in part (i), determine the sample size.The clinic management wanted to see 25% smaller margin of error but with

Solution: Given information: n= 15 Sample size The 95% confidence interval for the mean wait time…

Answered: In order to reduce the wait times and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4, find: The t-value for a 95% confidence interval is:
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data. Also, conduct a hypothesis, with alpha = 0.05, test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. Construct a 95% confidence interval Which of the following correctly displays the standard error? 0.0046 0.009 0.001 0.00002 0.008
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Using Rguroo, and the Large Sample Z method, calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived. Round your answers to 4 decimal places.
A popular weight loss program claims that with its recommended healthy diet regimen, users lose significant weight within a month. In order to estimate the mean weight loss of all customers, a nutritionist takes a sample of 18 dieters and records their weight loss one month after joining the program. He computes the sample mean of weight loss as 12.5 pounds and the sample standard deviation of weight loss as 9.2 pounds. Compute the 90% confidence interval for the population mean. (Round to two decimal places.)
An auditor of the USPS wants to examine its special two day mail handling to determine the proportion of parcels that actually arrive within the promised two day period. A randomly selected sample of 1600 such parcels is found to contain 1250 that were delivered on time. The USPS claims that more than 75% of parcels are delivered on time. Does a 95% confidence interval support this claim?
The national fire protection association reported that house fires in the United States result in $6.8billion in losses annually. Suppose a random sample of 50 house fires in San Antonio yields a mean loss of $18503. If the population standard deviation is $3300, what is the margin of error for a 95% confidence interval? What would you recommend if the study required a margin of error of $300 or less
A 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4. The 95% confidence interval between the difference in rates between the two departments (round off to three decimals) is:
From a research survey, it was found that a random sample of 18 elementary graduates of an exclusive private school has a mean NEAT score of 90 with a standard deviation of 16, while a random sample of 24 elementary graduates of a public school showed a mean NEAT score of 85 with a standard deviation of 12. Is there a significant difference in the NEAT performance of these two groups of elementary graduates? a. Use the traditional method, and b. The P-value method c. Construct a 95% confidence interval for the difference in mean.
An auditor of the USPS wants to examine its special two day mail handling to determine the proportion of parcels that actually arrive within the promised two day period. A randomly selected sample of 1600 such parcels is found to contain 1250 that were delivered on time. Use this to construct a 95% confidence interval for the parcels delivered on time.
In a simple random sample of 38 bulbs, 25 gives a good glow, What is a 85% score Confidence interval CI for the true proportion of the bulbs that gives good glow
Suppose a different police department says their SRS resulted in a 95% confidence interval of 10.1% to 15.1%. What is their point estimator and margin of error?
Based on a large sample of capacitors of a certain type, a 95% confidence interval for the mean capacitance, in �й, was computed to be (0.213,0.241). Find a 90% confidence interval for the mean capacitance of this type of capacitor.

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