coding language c++ Sample Output #3:Enter the diamond’s width: -2Please enter a width of at least 3.Enter the diamond’s width: 3*** Assignment4B: Diamonds in the sky.In our earliest labs, we asked you to print a diamond pattern to the screen using predefined printstatements. Now that we know how to use loops, we can make more dynamic and customizablepatterns.For this assignment, we will prompt the user to enter a maximum width for the diamond. If theyenter a number less than 3, we'll prompt them to choose a correct width. If they enter an evennumber (greater than 3), we will add 1 to it and let the user know the final diamond size. Thenwe will generate and print out the diamond using * and '' symbols.Hints: Each line of the "diamond" is made up of two parts – the asterisks in the centerand the spaces to the left of it. The amount of "left space" decreases as we go towardsthe middle diamond, then increases afterwards as we go towards the bottom. Could weuse multiple loops (or even nested loops) to model this behavior? Also, note that thenumber of asterisks increases (and later decreases) by two on each line.Call the file name Assignment4B(.java, .cs, .cpp) and the class name Assignment4B.User input is indicated in boldSample Output #1:Enter the diamond's width: 5***********Sample Output #2:Enter the diamond’s width: 8To make a diamond, we'll use 9 as the width instead.************************************

Code: #include <bits/stdc++.h>using namespace std;void Diamond(int n){ int gap = n - 1; for…

Answered: In our earliest labs, we asked you to…

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter6: Looping

Section: Chapter Questions

Problem 2GZ

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The code below is an example of what kind of loop? int x= 0; while(x<10) { x--; }
(In Java) Mathletes Game! With the introduction of loops, we now know enough about programming to begincreating simple games. Our first game (sponsored by the KSU College of Science and Mathematics)will test your ability to solve multiplication problems.Your game will first ask the player if they want to play on easy or hard mode. Save their response inan appropriate variable (you will reference it later). Then, you will randomly generate two numbersand display them to the player in the form of a multiplication problem. The possible numbers willrange between -255 and 255.You will ask the player to solve the equation. You will keep creating multiplication questions until theplayer wins or loses.Based on whether the player chose “hard” or “easy” mode, the game will play a little differently.Refer to the following rules for the difference:Easy Mode Hard ModePlayer only has to answer 5 questions Player has to answer 10 questionsPlayer can try again if they get a question wrong(up to two…
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JavaScript imageMosaic: compute image mosaic. You must implement the final version of the image mosaic algorithm we discussed in class (which includes the scaling of mosaic images and also randomization). Since the algorithm involves several nested loops and can take a while to run, this function will be implemented using a non-blocking loop so that the browser will not complain about its running speed. Details are in the comments embedded in the code. function imageMosaic(input, output, mosaic_name) { let width = input.width; let height = input.height; let mimages = mosaics[mosaic_name]; // mimages is an array of mosaic images let w = mimages[0].width; // all mosaic images have the same size wxh let h = mimages[0].height; let num = mimages.length; // number of mosaic images console.log('Computing Image Mosaic...'); let y = 0; (function chunk() { for(x = 0; x <= width-w; x += w) { // x loop // ===YOUR CODE STARTS HERE=== /* for(y=0; y<=input.height-h; y+=h) { for (x=0;…
Write a class called NestedLoop that prints the below picture. Use a for nested loop. No credit if nested loop is not used. Please Show your code and the console with the code.
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How do I change this to a for next loop Private Sub btnNames_Click(sender As Object, e As EventArgs) Handles btnNames.Click Dim x As Integer = 0 Do While x < cboNames.Items.Count MessageBox.Show("Name #" & x + 1 & " is " & cboNames.Items.Item(x)) x += 1 Loop End Sub
Q1: Telling in detail what is the "for" loop doing, how it works, and what is the last statement doing? Q2: How do you know it break down the loop? which one is control it? Telling the detail. Q3: It is direct access. you do not move from beginning. Give me the code. Q4; Which direction to move and from which side to starting? Write a set of Java Code for it, too. Q5: Write a set of code, too.
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