In part c. Why is h3 taken as hf? Explain the Q lost = Q gained in the picture as well as the graph. Thank you

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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In part c. Why is h3 taken as hf? Explain the Q lost = Q gained in the picture as well as the graph. Thank you
heg:2359 4 Kalky
h2=hf+xhfg, (251-5)+ (0.9 47123s84)
h2:2597.40 kJ lkg
Step3
c)
h3:hf: 2515 ks /1iky
Qlost : Bgained
mi(hg-hs)= meut lp(Teo-Ti)
447200 (2547.4-251-5): micwd 4.187(21-12)
3600
micw: 124.57 kg ls
P-v diagea-a T-s diageam
PT
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Transcribed Image Text:heg:2359 4 Kalky h2=hf+xhfg, (251-5)+ (0.9 47123s84) h2:2597.40 kJ lkg Step3 c) h3:hf: 2515 ks /1iky Qlost : Bgained mi(hg-hs)= meut lp(Teo-Ti) 447200 (2547.4-251-5): micwd 4.187(21-12) 3600 micw: 124.57 kg ls P-v diagea-a T-s diageam PT Was this solution helpful? ?
Given Data
Prz blo.44mm Hh vai
X= 0.9947
m: 7200 kglho+(1)
Tei=12°%
Tro = 21°c
To Rind mcw
Step2
Pabs: Pahm- Pc
Pabs: (101:325)- (13600x 610-44X 10% 9. kPa
1000
Pabs. (9.8 Py
Prom 8team hables at P=19:88KP
hf:251-5 Kolky hg:23594 K3/kg
h2=hf+xhfg, (251 5)+ (0.9947x23s94)
h2:2597-40 kJ lkg
Step3
c)
Qlost : 8gained
Transcribed Image Text:Given Data Prz blo.44mm Hh vai X= 0.9947 m: 7200 kglho+(1) Tei=12°% Tro = 21°c To Rind mcw Step2 Pabs: Pahm- Pc Pabs: (101:325)- (13600x 610-44X 10% 9. kPa 1000 Pabs. (9.8 Py Prom 8team hables at P=19:88KP hf:251-5 Kolky hg:23594 K3/kg h2=hf+xhfg, (251 5)+ (0.9947x23s94) h2:2597-40 kJ lkg Step3 c) Qlost : 8gained
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