1) The equation for finding the water head in an open channel flow is given below. is given. In this equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units) Since the height of the water in the channel is estimated to be between x1=0 and x2=2 units, What is the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of the approximate error.) continue until it is lower than and take six digits after the comma) 0.471405 x ( BH)5/3 (в + 2хН)2/3 f(H) = %3D

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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1) The equation for finding the water head in an open channel flow is given below. is given. In this
equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units)
Since the height of the water in the channel is estimated to be between x1-0 and x2=2 units, What is
the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of
the approximate error.) continue until it is lower than and take six digits after the comma)
0.471405 x ( BH)5/%
f(H) =
%3D
(B + 2 x H)2/3
Transcribed Image Text:1) The equation for finding the water head in an open channel flow is given below. is given. In this equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units) Since the height of the water in the channel is estimated to be between x1-0 and x2=2 units, What is the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of the approximate error.) continue until it is lower than and take six digits after the comma) 0.471405 x ( BH)5/% f(H) = %3D (B + 2 x H)2/3
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