In Problems 37 to 40, evaluate the triple integrals. -2x 37. dz dy dx 38. dy da dz 2=0 y=82 -2 2y+%3 -2x 1/z 39. 6y dx dz dy 40. z dy dz dr. y=-2 Jz=1 Jx=y+z r=1 Jz=r

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