In tae-kwon-do, a hand is slammed down onto a target at a speed of 10 m/s and comes to a stop during the 3.0 ms collision. Assume that during the impact the hand is independent of the arm and has a mass of 0.60 kg. What are the magnitudes of the (a) impulse and (b) average force on the hand from the target?

Question
Asked Oct 19, 2019

In tae-kwon-do, a hand is slammed down onto a target at a speed of 10 m/s and comes to a stop during the 3.0 ms collision. Assume that during the impact the hand is independent of the arm and has a mass of 0.60 kg. What are the magnitudes of the (a) impulse and (b) average force on the hand from the target?

check_circleExpert Solution
Step 1

Given:

Mass of the hand = 0.6 kg

Speed of the hand = 10 m/s

Time of impact = 3 ms

Step 2

Calculating the impulse:

Initial velocity of the hand = 10m/s
Final velocity of the hand = 0 m/s
Mass of the hand = 0.6 kg
Impulse is defined as change in momentum
Hence, Impulse, I = Ap
m(Av)
I m(Av)(0.6kg)x (10m/s-Om/ s)
I 6 kgm/s
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Initial velocity of the hand = 10m/s Final velocity of the hand = 0 m/s Mass of the hand = 0.6 kg Impulse is defined as change in momentum Hence, Impulse, I = Ap m(Av) I m(Av)(0.6kg)x (10m/s-Om/ s) I 6 kgm/s

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Step 3

Calculating the ave...

m(Av)
(Ar)
Average force
(0.6kg)(10m/s- Om/s)
(3x10s)
Substituting the values, Average force =
Or Average force = 2000 N
help_outline

Image Transcriptionclose

m(Av) (Ar) Average force (0.6kg)(10m/s- Om/s) (3x10s) Substituting the values, Average force = Or Average force = 2000 N

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