In the ammonia (NH3) molecule, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance d = 94.0 pm (picometer) from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen-to-hydrogen distance is L = 101.4pm. What are the (a)x and (b)y coordinates of the molecule's center of mass?  [Answer: (a) 0; (b)31.3 pm]. SHOW work, work needs to be shown

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter2: Atoms Molecules And Ions
Section2.8: Instrumental Analysis: Determining Compound Formulas
Problem 3.1ACP: To determine the density of atmospheric nitrogen. Lord Rayleigh removed the oxygen, water, and...
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In the ammonia (NH3) molecule, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance d = 94.0 pm (picometer) from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen-to-hydrogen distance is L = 101.4pm. What are the (a)x and (b)y coordinates of the molecule's center of mass?  [Answer: (a) 0; (b)31.3 pm].

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