In the circuit below, write the KVL equation of the secondary side j102 102 j1o2 j 402 302 Select one: O a. None O b.0 = (- j10)lg+ (30 + j40)lL O c. 70 = (30 + j40)|L - j10lg O d. 0 = (30 + j40)lg - j10lL

In the circuit below, write the KVL equation of the secondary side j102 102 j1o2 j 402 302 Select one: O a. None O b.0 = (- j10)lg+ (30 + j40)lL O c. 70 = (30 + j40)|L - j10lg O d. 0 = (30 + j40)lg - j10lL

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A circuit branch is found to have an equivalent impedance of Z=120−j45Ω. It is given that this impedance is a series combination of a 120Ω resistor and another passive component. If the circuit has a sinusoidal voltage source whose frequency is 120 Hz. What is the value of the component in series with the 120Ω resistor? (Note: Express the value assuming a metric scaling of μ(10-6). Provide your answer in decimal form, up to 3 decimal places.)
1. A 70-Vac source has the following waveform. Determine: a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angle h. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 54.9124°h. v(t) = 98.9949sin(20πt - 54.9124°)i. 29.0880 Vj. 108.8253°k. 66.8639 msGive the solution for K ONLY Ans: 66.8639 ms
Read A 70-Vac source has the following waveform. Determine:a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angleh. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms Give the solution for J and K ONLY ans (0.99959 degrees and 63.643 ms respectively)
Q10. If the impedance of a circuit = 20 – j10n, if a voltage source is connected across this impedance, which if the following statements is correct?
Find the phase relations for the following pairs of sinusoids. Sketch the curve e and i anddetermine which one LAGS and LEADS.a. v = 60 sin(377 t + 50°) V ; i = 3 sin(754t − 10°)A b. v = 6.4 sin(7.1 πt + 30°) V ; i = 7.3 sin(7.1 πt − 10°)A c. v = 42.3 sin(400 t + 60°) V ; i = −4.1 sin(400t − 50°)A
Suppose that the modulating signal m (t) is sinusoid of the formm (t) = 10 COS ( 2π103t) and the carrier signal C(t) is sinusoid of the form C(t) = 4 COS ( 2π106t + Ɵ)1. According to the previous results which type of AM is the best in respect toa. Power transmitted b. band widthJustify your answers2. Draw the block diagram for both DSBSC and DSBFC with all parameters.
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An industrial plant has a real power demand of 650 kW at a power factor of 0.65 lagging. The power is supplied by a 3-phase line at voltage of 4.16 kV (line to line voltage). You were just hired and your first task is to find the size of capacitors (in μF) required to improve the power factor to 0.95 lagging. The capacitors will be connected in grounded Y. Find- a) Calculations of the apparent power and the reactive power before the connection of the capacitors, b) Calculations of the reactive power, reactance, and capacitance of a capacitor bank required to improve the power factor to 0.95 lagging c) Calculations of the apparent power and the reactive power after the connection of the capacitors. d) Drawing of the power triangle. In your sketch you must show the real, reactive, and apparent power before and after the power factor correction and highlight the reactive power supplied by the capacitor. e) Sketch of the capacitor connection. Note: frequency is 60 Hz.
Answer is j11.56