The following three elements are all connected in parallel: a 5 cos(80t + 90°)V voltage source, a 252 resistor and a 250µF capacitor. 05 What is the current, represented as a phasor I,, through the capacitor? (Assume the direction of the current is positive. ' The solution formula to this question is: V 5290 5290 Z- 25|| – j50 20 – j10 -0.1+ j0.2A On the Excel spreadsheet enter -0.1+j0.2 in the numerical block and A in the text block. Any of following inputs will be marked as incorrect: -0.1+0.2j, j0.2-0.1 and -0.1+J0.2.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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The following three elements are all connected in parallel: a 5 cos(80t + 90°)V voltage source, a 252
resistor and a 250µF capacitor.
05 What is the current, represented as a phasor I,, through the capacitor? (Assume the direction
of the current is positive. '
The solution formula to this question is:
V
5290
5290
Z- 25|| – j50
20 – j10
-0.1+ j0.2A
On the Excel spreadsheet enter -0.1+j0.2 in the numerical block and A in the text block. Any of
following inputs will be marked as incorrect: -0.1+0.2j, j0.2-0.1 and -0.1+J0.2.
Transcribed Image Text:The following three elements are all connected in parallel: a 5 cos(80t + 90°)V voltage source, a 252 resistor and a 250µF capacitor. 05 What is the current, represented as a phasor I,, through the capacitor? (Assume the direction of the current is positive. ' The solution formula to this question is: V 5290 5290 Z- 25|| – j50 20 – j10 -0.1+ j0.2A On the Excel spreadsheet enter -0.1+j0.2 in the numerical block and A in the text block. Any of following inputs will be marked as incorrect: -0.1+0.2j, j0.2-0.1 and -0.1+J0.2.
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