In the circuit shown, the 16.0-V battery is removed and reinserted with the opposite polarity, so that its negative terminal is now next to point a. The current (in A) in the circuit is 1.6 Ω 16.0 V a b 5.0 Ω 9.0 Ω 1.4 N 8.0 V O 1.41 O 0.47 O 2

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Faraday’s Law And Inductance
Section: Chapter Questions
Problem 12OQ
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In the circuit shown, the 16.0-V
battery is removed and reinserted
with the opposite polarity, so that its
negative terminal is now next to
point a. The current (in A) in the
circuit is
1.6 Ω 16.0 V
а
b
5.0 Ω
9.0 N
1.4 Ω 8.0V
ww
O 1.41
O 0.47
O 2
Transcribed Image Text:In the circuit shown, the 16.0-V battery is removed and reinserted with the opposite polarity, so that its negative terminal is now next to point a. The current (in A) in the circuit is 1.6 Ω 16.0 V а b 5.0 Ω 9.0 N 1.4 Ω 8.0V ww O 1.41 O 0.47 O 2
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