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In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. The driver of the Thunderbird realizes that she must make a pit stop, and she smoothly slows to a stop over a distance of 250 m. She spends 5.00 s in the pit and then accelerates out, reaching her previous speed of 71.0 m/s after a distance of 280 m. At this point how far has the Thunderbird fallen behind the Mercedes Benz, which has continued at a constant speed?

Question

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. The driver of the Thunderbird realizes that she must make a pit stop, and she smoothly slows to a stop over a distance of 250 m. She spends 5.00 s in the pit and then accelerates out, reaching her previous speed of 71.0 m/s after a distance of 280 m. At this point how far has the Thunderbird fallen behind the Mercedes Benz, which has continued at a constant speed?

check_circleAnswer
Step 1

Let AB is first interval and after the pit BC is second interval.

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Step 2

Let acceleration in first interval is a. So,

a =
2s
(71.0)
a
2x250
a -10.08 m/s2
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Image Transcriptionclose

a = 2s (71.0) a 2x250 a -10.08 m/s2

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Step 3

Negative sign show the deceleration. Now, let accelerat...

v' 2a's
a'=_2
2s
(71.0)
a'
2x 280
a' 9.001 m/s2
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Image Transcriptionclose

v' 2a's a'=_2 2s (71.0) a' 2x 280 a' 9.001 m/s2

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