In the depths of space, asteroid miners attach a cable between their 3,694.-kg spaceship and a relatively small 1476-kg asteroid. The ship and asteroid are initially at rest 751 m apart. They begin to "reel in" the asteroid under a constant tension of 512.0 N. We are going to calculate how long it takes take for them to meet. This is a somewhat complicated question involving several different concepts, so let's just take it step by step. 11. Draw free-body diagrams for the asteroid, and for the spaceship. 12. Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively. (a) aa = 0.3469 m/s²; a, = 0.1386 m/s² (b) aq = 0.1386 m/s²; a, = 0.3469 m/s² (c) aa = 0.1388 m/s²; a, = 0.2775 m/s² (d) aa = 0.2775 m/s²; a, = 0.1388 m/s² 13. Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship. (a) 0.2083 m/s² (b) 0.4163 m/s² (c) 0.1387 m/s² (d) 0.4855 m/s² 14. Calculate the time it takes for the asteroid and the spaceship to arrive at the same location. (a) 104 s (b) 84.9 s (c) 60.1 s (d) 55.6 s Find the gravitational force of attraction between the space-tugboat and the asteroid in the previous question, when they are at their initial separation. Should we have included this force in our considerations?
In the depths of space, asteroid miners attach a cable between their 3,694.-kg spaceship and a relatively small 1476-kg asteroid. The ship and asteroid are initially at rest 751 m apart. They begin to "reel in" the asteroid under a constant tension of 512.0 N. We are going to calculate how long it takes take for them to meet. This is a somewhat complicated question involving several different concepts, so let's just take it step by step. 11. Draw free-body diagrams for the asteroid, and for the spaceship. 12. Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively. (a) aa = 0.3469 m/s²; a, = 0.1386 m/s² (b) aq = 0.1386 m/s²; a, = 0.3469 m/s² (c) aa = 0.1388 m/s²; a, = 0.2775 m/s² (d) aa = 0.2775 m/s²; a, = 0.1388 m/s² 13. Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship. (a) 0.2083 m/s² (b) 0.4163 m/s² (c) 0.1387 m/s² (d) 0.4855 m/s² 14. Calculate the time it takes for the asteroid and the spaceship to arrive at the same location. (a) 104 s (b) 84.9 s (c) 60.1 s (d) 55.6 s Find the gravitational force of attraction between the space-tugboat and the asteroid in the previous question, when they are at their initial separation. Should we have included this force in our considerations?
Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter14: Fluid Mechanics
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Problem 14.30P: The United States possesses the ten largest warships in the world, aircraft carriers of the Nimitz...
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Transcribed Image Text:In the depths of space, asteroid miners attach a cable between their 3,694.-kg spaceship and a relatively small 1476-kg
asteroid. The ship and asteroid are initially at rest 751 m apart. They begin to “reel in" the asteroid under a constant tension
of 512.0 N. We are going to calculate how long it takes take for them to meet. This is a somewhat complicated question
involving several different concepts, so let's just take it step by step.
11.
Draw free-body diagrams for the asteroid, and for the spaceship.
12.
Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively.
(a) aa = 0.3469 m/s²; a, = 0.1386 m/s²
(b) aa = 0.1386 m/s²; a, = 0.3469 m/s²
(c) aa = 0.1388 m/s²; a̟ = 0.2775 m/s²
(d) aa = 0.2775 m/s²; a, = 0.1388 m/s²
Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship. i
(а) 0.2083 m/s?
(b) 0.4163 m/s²
(c) 0.1387 m/s²
(d) 0.4855 m/s²
13.
14.
Calculate the time it takes for the asteroid and the spaceship to arrive at the same location.
(а) 104 s
(b) 84.9 s
(c) 60.1 s
(d) 55.6 s
Find the gravitational force of attraction between the space-tugboat and the asteroid in the previous question, when
they are at their initial separation. Should we have included this force in our considerations?
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