In the figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords as shown in the figure here. One cord makes the angle e = 40.4° with the vertical; the other makes the angle o = 49.6° with the vertical. If the length L of the bar is 3.0 m, compute the distance x from the left end of the bar to its center of mass. L com X = i

Glencoe Physics: Principles and Problems, Student Edition
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Author:Paul W. Zitzewitz
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Chapter8: Rotational Motion
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In the figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords as
shown in the figure here. One cord makes the angle e = 40.4° with the vertical; the other makes the
angle o = 49.6° with the vertical. If the length Lof the bar is 3.0 m, compute the distance x from the
left end of the bar to its center of mass.
L
com
i
Transcribed Image Text:In the figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords as shown in the figure here. One cord makes the angle e = 40.4° with the vertical; the other makes the angle o = 49.6° with the vertical. If the length Lof the bar is 3.0 m, compute the distance x from the left end of the bar to its center of mass. L com i
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