In the figure, RQ Is tangent to drde P at polnt Q. What Is m/PRQ? Drag and drop the measures Into the boxes to complete the explanation. 61° Q. A line tangent to a circle is ? v to the radius drawn to the point of tangency. So, MZPQR = By the Triangle Sum Theorem, m/PRQ + MRPQ +m/PQR = Substituting the known values of m/PQR and m/RPQ into that equation and solving the resulting equation, you find that M/PRQ = 180° 29° 90°

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 5E
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In the figure, RQ Is tangent to drde P at polnt Q.What Is MZPRQ? Drag and drop the measures Into the
boxes to complete the explanation.
R
61°
Q.
A line tangent to a circle is
v to the radius drawn to the point of tangency. So,
m/PQR =
By the Triangle Sum Theorem, mZPRQ + MZRPQ + m<PQR =
Substituting the known
values of m/PQR and mZRPQ into that equation and solving the resulting equation, you find that
M/PRQ =
180°
29°
90°
Next Question
Question 2 of 11
Transcribed Image Text:Question In the figure, RQ Is tangent to drde P at polnt Q.What Is MZPRQ? Drag and drop the measures Into the boxes to complete the explanation. R 61° Q. A line tangent to a circle is v to the radius drawn to the point of tangency. So, m/PQR = By the Triangle Sum Theorem, mZPRQ + MZRPQ + m<PQR = Substituting the known values of m/PQR and mZRPQ into that equation and solving the resulting equation, you find that M/PRQ = 180° 29° 90° Next Question Question 2 of 11
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