Asked Oct 1, 2019

In the following reaction, how many grams of O2 must be reacted in order to produce 162 grams of N2O5 (MW = 108.0 g/mol) at a 80.0% yield? 2 N2H4(g) + 7 O2(g) → 2 N2O5(g) + 4 H2O(g)


Expert Answer

Step 1

First, the given N2O5 grams is converted into moles. The given ...


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2N,0 4HO 2N H70 Mass Moles Molar mass 162 g 108.01 g/mol = 1.50 moles


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