In the given question Wa = V3 radls and § = 0. 6 which means the system is under damped system. Damped frequency wa=wn V1 – =V3• V1 - 0.6 wa=1. 3856 radls 1. Time to reach its peak overshoot 3.14 1.3856 = 2. 267 sec tp Peak overshoot value Mp=e *0.6 =e Mp=0. 09478 2. Time to reach its third peak overshoot 5*3.14 = 11.336 sec 1.3856 tp Third peak overshoot value Mp=e _Vi Vi-062 =e Mp=7. 65 * 106

In the given question Wa = V3 radls and § = 0. 6 which means the system is under damped system. Damped frequency wa=wn V1 – =V3• V1 - 0.6 wa=1. 3856 radls 1. Time to reach its peak overshoot 3.14 1.3856 = 2. 267 sec tp Peak overshoot value Mp=e 0.6 =e Mp=0. 09478 2. Time to reach its third peak overshoot 53.14 = 11.336 sec 1.3856 tp Third peak overshoot value Mp=e _Vi Vi-062 =e Mp=7. 65 * 106

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter12: Lighting Branch Circuit And Small-appliance Circuits For The Kitchen

Section: Chapter Questions

Problem 5R: a. What is the minimum number of 20-ampere small-appliance circuits required for a kitchen according...

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