In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,O3) dissolved in molten cryolite (Na, AlF), resulting in the reduction of the Al,O, to pure aluminum. Suppose a current of 9000. A is passed through a Hall-Heroult cell for 18.0 seconds. Calculate the mass of pure aluminum produced. Be sure your answer has a unit symbol and the correct number of significant digits. olo

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Chapter17: Electrochemistry
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In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AIF6), resulting in
the reduction of the Al,0, to pure aluminum.
Suppose a current of 9000. A is passed through a Hall-Heroult cell for 18.0 seconds. Calculate the mass of pure aluminum produced.
Be sure your answer has a unit symbol and the correct number of significant digits.
x10
?
Transcribed Image Text:In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,0,) dissolved in molten cryolite (Na, AIF6), resulting in the reduction of the Al,0, to pure aluminum. Suppose a current of 9000. A is passed through a Hall-Heroult cell for 18.0 seconds. Calculate the mass of pure aluminum produced. Be sure your answer has a unit symbol and the correct number of significant digits. x10 ?
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