In the power and energy experiment, the power (PRL) dissipated across the load resistor R is given by the equation: P =g?_R2 (R+R¿)? 280 260 y = 102010x - 1E-12 240 R2 = 1 220 200 180 160 140 ........ .... 120 100 0.001 0.0015 0.002 0.0025 0.003 RL/(RL+R)² (1/Q) The value of gin volt is (mu)d
In the power and energy experiment, the power (PRL) dissipated across the load resistor R is given by the equation: P =g?_R2 (R+R¿)? 280 260 y = 102010x - 1E-12 240 R2 = 1 220 200 180 160 140 ........ .... 120 100 0.001 0.0015 0.002 0.0025 0.003 RL/(RL+R)² (1/Q) The value of gin volt is (mu)d
Chapter9: Current And Resistance
Section: Chapter Questions
Problem 63P: Consider a power plant is located 60 km away from a residential area uses Q-gauge (A=42.40mm2) wire...
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Transcribed Image Text:In the power and energy experiment, the power (PRI) dissipated across the load resistor R is given by the equation:
R,
(R+R¸)²
280
260
y = 102010x - 1E-12
R2 = 1
240
220
200
180
160
..... .... .. . .. ... ...
140
120
100
0.001
0.0015
0.002
0.0025
0.003
RL/(RL+R)² (1/Q)
The value of F in volt is
(mu)d
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