R2 R1 R3 R4 V Rs R6 In the above circuit, R1 = 102, R2 = 202, R3 = 150, R4 = 5N, R5 = 300 and R6 = 400. The battery voltage is 9V. 1. The equivalent resistance of the circuit is 2. The source current is A 3. The voltage drop across R5 is V 4. The current through R2 is A 5. The power dissipated across R1 is

R2 R1 R3 R4 V Rs R6 In the above circuit, R1 = 102, R2 = 202, R3 = 150, R4 = 5N, R5 = 300 and R6 = 400. The battery voltage is 9V. 1. The equivalent resistance of the circuit is 2. The source current is A 3. The voltage drop across R5 is V 4. The current through R2 is A 5. The power dissipated across R1 is

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter21: Circuits And Dc Instruments

Section: Chapter Questions

Problem 28PE: Integrated Concepts A 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being...

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Integrated Concepts A 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the battery’s internal resistance? (b) What power is dissipated inside the battery? (c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300 kcal/kg. °C, assuming no heat escapes?
Consider the circuit below, (a) What is the initial current through resistor R2? when the switch is closed? (b) What is die current through resistor R2 when the capacitor is fully charged, long after die switch is closed? (c) What happens if the switch is opened after it has been closed for some rime? (d) If the switch has been closed for a time period long enough for the capacitor to become fully charged, and then the switch is opened, how long before the current through resistor R1 reaches half of its initial value?
(a) Explain how the mnemonic ELI the ICE man can be used to recall whether current leads voltage or voltage leads current in RLC circuits. Note that E represents emf . (b) Explain how CIVIL works as another mnemonic device, where V represents voltage.
A 240-kV power transmission line carrying 5.00x102. A is hung from grounded metal towers by ceramic insulators, each having a 1.00x 109- resistance. Figure 21.51. (a) What is the resistance to ground of 100 of these insulators? (b) Calculate the power dissipated by 100 of them, (c) What fraction of the power carried by the line is this? Explicitly show how you follow the steps in the Problem-Solving Strategies for Series and Parallel Resistors.
The label on a battery-powered radio recommends the use of a rechargeable nickel-cadmium cell (nicads), although it has a 1.25-V emf, whereas an alkaline cell has a 1.58-V emf. The radio has a 3.20 resistance.(a) Draw a circuit diagram of the radio and its battery. Now, calculate the power delivered to the radio (b) when using a nicad cells, each having an internal resistance of 0.0400 , and (c) when using an alkaline cell, having an internal resistance of 0.200 . (d) Does this differenceseem significant, considering that the radio's effective resistance is lowered when its volume is aimed up?
A small office-building air conditioner operates or 408-V AC and consumes 50.0 kW. (a) What is its effective resistance? (b) What is the cost of running the air conditioner during a hot summer month when it is on 8.00 h per day for 30 days and electricity costs 9.00 cenls/kW h ?
The power dissipated in a resistor is given by P = V2/R, which means power decreases if resistance increases. Yet this power is also given by P = I2R, which means power increases if resistance increases. Explain why there is no contradiction here.
1.a. Which article of the National Electrical Code covers radio and television equipment?A. 770B. 517C. 810D. 7051.b. All _______-ampere receptacles for sensitive electronic equipment must be ground-fault circuitinterrupter protected.A. 10- and 30B. 10- and 15C. 20- and 30D. 15- and 20
R1 is 150 ohms, and R2 is 220 ohms. (150 +220 = 370). In a series circuit, the current is the same across the circuit. The available power storage is 6 volts. The problem I am have is conceptualizing what V1 + V2 equals. I conjecture that the sum would be less than 6 V. I can't say 3 + 3 =6 V, but rather V1 + V2 < 6? Unless R1=R2, then perhaps 3 + 3 = 6V. However, R1 is 150 ohms, and R2 is 220 ohms. Complicating issue, if I use an ammeter and voltmeter, these devices may have some internal resistance, so equals becomes < 6 V? How then do I conceptualize better, V1 + V2, so that maybe it is based on the value of the individual Resistor?
To get the minimum current, the connection should be in series. If you create a series connection with 30V DC source and three resistors with R1 = 50Ω, R2 = 75Ω, and R3 = 100Ω, how do you calculate for the total current (IT) and the current flowing in each resistor (I1, I2, I3), and the total voltage (VT) and the voltage across each resistor (V1, V2, V3)? How do you also determine the power dissipated by each resistor (P1, P2, P3) and by the whole circuit (PT)??
Create a circuit with four resistors linked to a source (EMF = 10V), where R1 and R2 should have the same current as the circuit's total current, while R3 and R4 should share this total current. R1 and R2 have the same values for the color bands red, black, red, and gold, whereas R3 and R4 have the same values for the color bands yellow, violet, brown, and gold.
3) Suppose a current is given by the equation I=1.70sin(250t), where I is in amperes and t in seconds. Part A What is the frequency? Part B What is the rms value of the current? Part C If this is the current through a 24.0 Ω resistor, write the equation that describes the voltage as a function of time. a) V=(1/40.8)sin(250t) b) V=40.8sin(250t/2) c) V=40.8sin(250t) d) V=40.8sin(2⋅250t)