In the presence of CN-, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 x 10-40 M and 1.5 x 10-3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)6 3-. Fe3+(aq) + 6CN-(aq) ⇌ Fe(CN )63-(aq) Koverall  = ?

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Chapter16: Solubility And Complex Ion Equilibria
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Problem 63E: In the presence of CN, Fe3+ forms the complex ion Fe(CN)63. The equilibrium concentrations of Fe3+...
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In the presence of CN-, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 x 10-40 M and 1.5 x 10-3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)6 3-.

Fe3+(aq) + 6CN-(aq) ⇌ Fe(CN )63-(aq) Koverall  = ?

 

                        

 

 

 

 

 



 

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