The overall formation constant for Fe(CN)6³- is 1.0x104². K₁= [Fe(CN)6³-] [Fe³+][CN 16 -=1.0×104² 3- What will be the equilibrium concentrations of Fe³+, CN- and Fe(CN)6³ in 500.0 mL of a solution that was originally 0.15 M Fe³+ and 1.20 M CN-? a. [Fe3+] b. [CN-] c. [Fe(CN)6³-]
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Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
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![The overall formation constant for Fe(CN)6³ is 1.0×104².
3-
[Fe(CN)6³-]
K₁=
-=1.0×104²
[Fe³+][CN 16
3-
What will be the equilibrium concentrations of Fe³+, CN- and Fe(CN)6³ in 500.0 mL of a solution that
was originally 0.15 M Fe³+ and 1.20 M CN-?
a. [Fe3+]
b. [CN-]
c. [Fe(CN)6³-]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8dd5ecd4-9d74-4d0a-a174-44f6ad2c456d%2F8ac5083b-dad4-4109-a02c-88e0c00b2396%2Fgwwzioh_processed.png&w=3840&q=75)
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