In the process of solving 2x3+7x2+9x+10=0, you test 1, 2, 5, and 10 as possible zeros and determine that none of them are actual zeros. You then discover that -5/2 is a zero and the quotient upon dividing by (x + 5/2) to be 2x2+2x+4. Do you need to test 1, 2, 5, and 10 again? Why or why not?
In the process of solving 2x3+7x2+9x+10=0, you test 1, 2, 5, and 10 as possible zeros and determine that none of them are actual zeros. You then discover that -5/2 is a zero and the quotient upon dividing by (x + 5/2) to be 2x2+2x+4. Do you need to test 1, 2, 5, and 10 again? Why or why not?
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 19PT: Use Descartes’ Rule of Signs to determine the possible number of positive and negative solutions....
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In the process of solving 2x3+7x2+9x+10=0, you test 1, 2, 5, and 10 as possible zeros and determine that none of them are actual zeros. You then discover that -5/2 is a zero and the quotient upon dividing by (x + 5/2) to be 2x2+2x+4. Do you need to test 1, 2, 5, and 10 again? Why or why not?
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