In the rate law equation, where can the exponent of a reactant be derived? O From the results of initial rates experiment O From its coefficient in a balanced equation O From the integration of the rate expression O The exponent is a constant.

Chemistry In Focus
7th Edition
ISBN:9781337399692
Author:Tro, Nivaldo J.
Publisher:Tro, Nivaldo J.
Chapter8: Nuclear Chemistry
Section: Chapter Questions
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Question 21
One of the disadvantages of SEM is radiation exposure. What is the source of this radiation?
O UV
Auger
Phopshor
X-ray
Transcribed Image Text:Question 21 One of the disadvantages of SEM is radiation exposure. What is the source of this radiation? O UV Auger Phopshor X-ray
Question 22
In the rate law equation, where can the exponent of a reactant be derived?
O From the results of initial rates experiment
From its coefficient in a balanced equation
From the integration of the rate expression
O The exponent is a constant.
Transcribed Image Text:Question 22 In the rate law equation, where can the exponent of a reactant be derived? O From the results of initial rates experiment From its coefficient in a balanced equation From the integration of the rate expression O The exponent is a constant.
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