in the reaction Ba(NO3)2+H2SO4 =BaSO4+2HNO3 how many grams of Ba(NO3)2 are required to precipitate the sulfate ion present in 15.3 ml of 0.139M H2SO4

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in the reaction

Ba(NO3)2+H2SO4 =BaSO4+2HNO3

how many grams of Ba(NO3)2 are required to precipitate the sulfate ion present in 15.3 ml of 0.139M H2SO4? 

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