How many milliliters of 0.592 M KOH are needed to react completely with 55.0 mL of 0.271 M FeCl2 solution to precipitate Fe(OH)2? The net ionic equation is: Fe2*(aq) + 20H'(aq) → Fe(OH)2(s) VKOH = i mL

Introductory Chemistry: A Foundation
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Problem 95AP: 95. Many metal ions form insoluble sulfide compounds when a solution of the metal ion is treated...
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How many milliliters of 0.592 M KOH are needed to react completely with 55.0 mL of 0.271 M FeCl2 solution to precipitate Fe(OH)2?
The net ionic equation is:
Fe2+(aq) + 20H(aq) → Fe(OH)2(s)
VKOH =
i
mL
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Transcribed Image Text:How many milliliters of 0.592 M KOH are needed to react completely with 55.0 mL of 0.271 M FeCl2 solution to precipitate Fe(OH)2? The net ionic equation is: Fe2+(aq) + 20H(aq) → Fe(OH)2(s) VKOH = i mL eTextbook and Media Save for Later Attempts: 0 of 15 used Submit Answer A O S OCT étv 14 MacBook Air
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