In this assignment, I would like you to compute the chi-square goodness of fit testfor an observed data set, using two different MOIS. A critically important point inour work is that MOI just means the proportions that correspond to the differentphenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and SexLinked Recessive (SLR). The data in the table below is the counts of F2 offspringfrom an F1 cross. We use the following notation for the alleles at thegeneof interest:Notation:D= disease allele at gened = wild-type allele at gene%3DLet's provide some information about each MOI.AD: Each of the Fi parents is heterozygous for the D allele.SLR: The observed F2 data are the offspring from an F1 cross where the father isaffected (disease) and the mother is an unaffected carrier (wild-type, or WT). Thatis, the mother's genotype has one disease allele and one WT allele in it.In Table 1, I provide the observed data counts (in dark blue). Notice that I stratifyby gender.Table 1.(0-E)²(0-E)?/EPhenotypeDisease, MaleDisease, FemaleWT, MaleWT, FemaleTotalEO-E3042672853011157DFp-value

Given Information:Consider the data that shows the observed counts of F2 offspring from an F1 cross.…

In this assignment, I would like you to compute the chi-square goodness of fit test for an observed data set, using two different MOIS. A critically important point in our work is that MOI just means the proportions that correspond to the different phenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and Sex Linked Recessive (SLR). The data in the table below is the counts of F2 offspring from an F1 cross. We use the following notation for the alleles at the gene of interest: Notation: D= disease allele at gene d = wild-type allele at gene Let's provide some information about each MOI. AD: Each of the Fı parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother's genotype has one disease allele and one WT allele in it. s one In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1. (O-E)² (O-E)’/E Phenotype Disease, Male Disease, Female WT, Male WT, Female Total E О-Е 304 267 285 301 1157 DF p-value

In this assignment, I would like you to compute the chi-square goodness of fit test for an observed data set, using two different MOIS. A critically important point in our work is that MOI just means the proportions that correspond to the different phenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and Sex Linked Recessive (SLR). The data in the table below is the counts of F2 offspring from an F1 cross. We use the following notation for the alleles at the gene of interest: Notation: D= disease allele at gene d = wild-type allele at gene Let's provide some information about each MOI. AD: Each of the Fı parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother's genotype has one disease allele and one WT allele in it. s one In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1. (O-E)² (O-E)’/E Phenotype Disease, Male Disease, Female WT, Male WT, Female Total E О-Е 304 267 285 301 1157 DF p-value

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.3: Measures Of Spread

Problem 1GP

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