In titration of 35 ml 0.046 M Fe2* with 0.056 M Ce4* what is the cell voltage at the equivalence point? E(calomel) = 0.241 V Fe3+ + e¯ 2 Fe²+ E° = 0.767 V Ce4+ + e- = Ce3+ E° = 1.70 V Buret containing Ce Calomel

In titration of 35 ml 0.046 M Fe2* with 0.056 M Ce4* what is the cell voltage at the equivalence point? E(calomel) = 0.241 V Fe3+ + e¯ 2 Fe²+ E° = 0.767 V Ce4+ + e- = Ce3+ E° = 1.70 V Buret containing Ce Calomel

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.29QAP

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Question

In titration of 35 ml 0.046 M Fe2* with 0.056 M Ce4* what is the cell
voltage at the equivalence point?
E(calomel) = 0.241 V
Fe3+ + e¯ = Fe²+
E° = 0.767 V
Ce4+ + e- = Ce3+
E° = 1.70 V
Buret containing Ce
Calomel

Calomel
- reforence
electrode
Fe in 1 M HCIO,
-Pt wire
Magnetic
string bar
Lütfen birini seçin:
а.
1.7 V
b.
2.54 V
0.767 V
d.
1.98 V
O e.
0.99 V

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