Incorrect Your answer is incorrect. Suppose a 500. mL flask is filled with 0.90 mol of NO2, 1.4 mol of CO and 1.0 mol of NO. The following reaction becomes possible: NO2(g) +CO(g) = NO(g) +CO2(g) The equilibrium constant K for this reaction is 8.93 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. 0.69 M ☑

General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.13QP: A chemist put 1.18 mol of substance A and 2.85 mol of substance B into a 10.0-L flask, which she...
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Incorrect
Your answer is incorrect.
Suppose a 500. mL flask is filled with 0.90 mol of NO2, 1.4 mol of CO and 1.0 mol of NO. The following reaction becomes possible:
NO2(g) +CO(g) = NO(g) +CO2(g)
The equilibrium constant K for this reaction is 8.93 at the temperature of the flask.
Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
0.69 M
☑
Transcribed Image Text:Incorrect Your answer is incorrect. Suppose a 500. mL flask is filled with 0.90 mol of NO2, 1.4 mol of CO and 1.0 mol of NO. The following reaction becomes possible: NO2(g) +CO(g) = NO(g) +CO2(g) The equilibrium constant K for this reaction is 8.93 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. 0.69 M ☑
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