"Inert" xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XEF4, and XeF, are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the heat of formation is –402 kJ/mol.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter6: Covalent Bonding
Section: Chapter Questions
Problem 81QRT: Tribromide, Br3, and triiodide, I3, ions are often found in aqueous solutions, but trifluoride ion,...
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"Inert" xenon actually forms several compounds, especially with the highly electronegative elements
oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF, are all formed by direct reaction of the
elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one.
Calculate the Xe-F bond energy in XeF6, given that the heat of formation is -402 kJ/mol.
Transcribed Image Text:"Inert" xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF, are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the heat of formation is -402 kJ/mol.
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The heat of formation of a compound is numerically equal to the net energies when all the bonds of the given compound are formed.

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