ing Two resistors, R1 = 2.57 Q and R2 = 5.81 Q, are connected in series to a battery with an EMF of 24.0 V and negligible internal resistance. Find the current I, through R¡ and the potential difference V½ across R2. R2 A V V2 =

ing Two resistors, R1 = 2.57 Q and R2 = 5.81 Q, are connected in series to a battery with an EMF of 24.0 V and negligible internal resistance. Find the current I, through R¡ and the potential difference V½ across R2. R2 A V V2 =

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter28: Current And Resistance

Section: Chapter Questions

Problem 67PQ

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Question

Two resistors, R, = 2.57 2 and R, = 5.81 2, are connected
in series to a battery with an EMF of 24.0 V and negligible
internal resistance. Find the current I, through R1 and the
potential difference V½ across R2.
I =
A
R2
V½ =
V

Expert Solution

Step 1

Given:

$R_{1} = 2.57 Ω R_{2} = 5.81 Ω$

The emf of the battery is 24 V.

Step by step

Solved in 2 steps

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