Initial (M) Change (M) Equilibrium (M) 0.400 + x Predict the equilibrium concentration of IBr in the reaction described below by constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. 12(g) + Br₂(g) 2 IBr(g) Tap here or pull up for additional resources In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach equilibrium. Fill in the ICE table with the appropriate value for each involved species to determine the partial pressures of all reactants and products. Where applicable, use the x variables to represent any unknown change in concentration. 0 1 0.400+ 2x 0.400 1₂(g) 0.400 - x 0.133 2 0.400 - 2x + +x 0.133 + x 3 Br₂(g) +2x 0.133 + 2x NEXT > -X 0.133 - x 2 IBr(g) RESET -2x 0.133 - 2x

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 8ALQ
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The value of Kc is 280 at a specific temperature. Based on your ICE table (Part 1),
set up the equilibrium expression for Kc in order to determine concentrations of all
species. Each reaction participant must be represented by one tile. Do not
combine terms.
[x]
[0.133 + 2x]
[0.133 + 2x]²
Predict the equilibrium concentration of IBr in the reaction described
below by constructing an ICE table, writing an equilibrium
expression for Kc, and solving for the equilibrium concentration.
Complete Parts 1-3 before submitting your answer.
12(g) + Br₂(g) 2 IBr(g)
Tap here or pull up for additional resources
[2x]
[0.133 -x]
[0.133 - x]²
1
Kc =
Кс
[2x]²
[0.133 - 2x]
[0.133 - 2x]²
[0.400 + x]
[0.400 + x]²
[0.400 + 2x]
[0.400 + 2x]²
3
= 280
[0.400 -x]
[0.400 -x]²
[0.400 - 2x]
[0.400 - 2x]²
RESET
[0.133 + x]
[0.133 + x]²
Transcribed Image Text:< PREV NEXT > The value of Kc is 280 at a specific temperature. Based on your ICE table (Part 1), set up the equilibrium expression for Kc in order to determine concentrations of all species. Each reaction participant must be represented by one tile. Do not combine terms. [x] [0.133 + 2x] [0.133 + 2x]² Predict the equilibrium concentration of IBr in the reaction described below by constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. 12(g) + Br₂(g) 2 IBr(g) Tap here or pull up for additional resources [2x] [0.133 -x] [0.133 - x]² 1 Kc = Кс [2x]² [0.133 - 2x] [0.133 - 2x]² [0.400 + x] [0.400 + x]² [0.400 + 2x] [0.400 + 2x]² 3 = 280 [0.400 -x] [0.400 -x]² [0.400 - 2x] [0.400 - 2x]² RESET [0.133 + x] [0.133 + x]²
Initial (M)
Change (M)
Equilibrium (M)
0.400 + x
Predict the equilibrium concentration of IBr in the reaction described
below by constructing an ICE table, writing an equilibrium
expression for Kc, and solving for the equilibrium concentration.
Complete Parts 1-3 before submitting your answer.
12(g) + Br₂(g) 2 IBr(g)
Tap here or pull up for additional resources
In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach
equilibrium. Fill in the ICE table with the appropriate value for each involved
species to determine the partial pressures of all reactants and products. Where
applicable, use the x variables to represent any unknown change in concentration.
0
1
0.400 + 2x
1₂(g)
[0]
0.400
0.400 - x
0.133
2
0.400 - 2x
+
+x
3
Br₂(g)
0.133 + x
110
+2x
0.133 + 2x
NEXT >
-X
0.133 - x
2 IBr(g)
000
RESET
-2x
0.133 - 2x
Transcribed Image Text:Initial (M) Change (M) Equilibrium (M) 0.400 + x Predict the equilibrium concentration of IBr in the reaction described below by constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. 12(g) + Br₂(g) 2 IBr(g) Tap here or pull up for additional resources In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach equilibrium. Fill in the ICE table with the appropriate value for each involved species to determine the partial pressures of all reactants and products. Where applicable, use the x variables to represent any unknown change in concentration. 0 1 0.400 + 2x 1₂(g) [0] 0.400 0.400 - x 0.133 2 0.400 - 2x + +x 3 Br₂(g) 0.133 + x 110 +2x 0.133 + 2x NEXT > -X 0.133 - x 2 IBr(g) 000 RESET -2x 0.133 - 2x
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