int A[3] [4]={{ 4, 6, 7, 9},{ 1, 3, 4, 3},{-5, 6, 7, 2}}; int sum,row,col; sum 0; for (col=0;col<=3;i++) sum+=A[0] [col]; what is the value of sum calculated the number of elements on row 0 the total addition of elements on row 0 the total addition of first 3 elements on row 0 the total addition of all the elements
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- in java Integer numElements is read from input, representing the number of integers to be read next. Then, the remaining integers are read and stored into array valuesArray. For each element in valuesArray that is divisible by 9, assign the element with the element's current value plus 1. Ex: If the input is: 3 81 99 30 then the output is: Original values: 81 99 30 New values: 82 100 30 Note: (x % 9 == 0) returns true if x is divisible by 9. 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 for (i=0; i<valuesArray.length; ++i) { valuesArray[i] =scnr.nextInt(); } System.out.print("Original values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); /* Your code goes here */ System.out.print("New values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); } }Parameters array - Any JavaScript Array size - A positive integer Number indicating the desired "chunk" size. Return Value A new Array of Arrays. Each sub-Array has a length equal to size. Remaining elements are gathered into a final sub-Array. Do not mutate the input array Do not use Array.prototype.slice in your implementation.Do not use Array.prototype.shift in your implementation.Do not use Array.prototype.pop in your implementation.Do not use Array.prototype.splice in your implementation. Please fix this JavaScript function so that the when calling the function with the parameters chunk([false, true, false, true], 3); the output is [[false, true, false], [true]] (subarrays)and when the parameters are chunk([undefined, null, 0, false, NaN, ""], 3); the output is [[undefined, null, 0], [false, NaN, ""]] thank you very much! function chunk(ar, sz) { var res = []; var ind = 0; // itterating through the new length of resulting array for (var i = 0; i < ar.length / sz; i++)…Java Program. Write a function that returns the index of the smallest element in an array of doubles. If there are more such elements than one, return the last index is fine. Using the following header: int IndexOfSmallestArray(double array[], int size) Finish the function implement only.
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