Integers seedVal and largestVal are read from input. Assign variables in1, in2, and in3 each with a random number in the range o 0 to largestVal - 1, inclusive. Ex: If largestVal is 14, then one possible output is: 12 3 10 Sum: 25 Note: The input seeds are large integers that approximately equal the time in seconds since January 1, 1970. 1 #include 2 #include 3 #include 4 using namespace std; 5 6 int main() { 7 8 9 10 11 12 13 14 15 16 17 18 int seedVal; int sum; int largestVal; int in1; int in2; int in3; cin >> seedVal; cin >> largestVal; srand (seedVal);

Integers seedVal and largestVal are read from input. Assign variables in1, in2, and in3 each with a random number in the range o 0 to largestVal - 1, inclusive. Ex: If largestVal is 14, then one possible output is: 12 3 10 Sum: 25 Note: The input seeds are large integers that approximately equal the time in seconds since January 1, 1970. 1 #include 2 #include 3 #include 4 using namespace std; 5 6 int main() { 7 8 9 10 11 12 13 14 15 16 17 18 int seedVal; int sum; int largestVal; int in1; int in2; int in3; cin >> seedVal; cin >> largestVal; srand (seedVal);

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter2: Basic Elements Of C++

Section: Chapter Questions

Problem 33SA

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4.15 LAB: Hailstone sequence Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 My Code: n = int(input())print(n, end='\t')i = 1while n > 1: if not i % 10: print(n, end='\n') if n % 2 == 0: n = n//2 print(n, end='\t') else: n = 3*n+1 print(n, end='\t') i += 1print() Output: Screenshot attached!
4.15 LAB: Hailstone sequence Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1
Birthday party At Lili's birthday party, there was a game arranged by Jojo as the host. That game is to distribute Y number of candy to X number of people where all the candy tastes sweet except for one last candy which tasted like rotten nuts. Candy distribution will be sequentially starting from position Z and if past the last position then the distribution of candy continues to the first position. Write down the person in which position will get the last candy. Input FormatThe first line of input is T, which is the number of test cases.The second row and the next number of T rows are X, Y, Z.X is the number of people to whom the candy will be distributed.Y is the number of candy available.Z is the starting position of the person to whom the candy will be distributed. Output FormatA string “Case #N: “ and a number representing the position of the person who got the last candy. Constraints1 ≤ T ≤ 1001 ≤ X, Y ≤ 1031 ≤ Z ≤ X Sample Input 43 4 13 5 24 2 24 5 2 Sample OutputCase #1: 1Case…
Birthday party At Lili's birthday party, there was a game arranged by Jojo as the host. That game is to distribute Y number of candy to X number of people where all the candy tastes sweet except for one last candy which tasted like rotten nuts. Candy distribution will be sequentially starting from position Z and if past the last position then the distribution of candy continues to the first position. Write down the person in which position will get the last candy. Input FormatThe first line of input is T, which is the number of test cases.The second row and the next number of T rows are X, Y, Z.X is the number of people to whom the candy will be distributed.Y is the number of candy available.Z is the starting position of the person to whom the candy will be distributed. Output FormatA string “Case #N: “ and a number representing the position of the person who got the last candy. Constraints? ≤ ? ≤ ???? ≤ ?, ? ≤ ???? ≤ ? ≤ X Sample Input 43 4 13 5 24 2 24 5 2 Sample OutputCase #1: 1Case…
19.3 LAB: Hailstone sequence Given a positive integer n, the following rules will always create a sequence that ends with 1, called the hailstone sequence: If n is even, divide it by 2 If n is odd, multiply it by 3 and add 1 (i.e. 3n +1) Continue until n is 1 Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. The output format can be achieved as follows:print(n, end='\t') Ex: If the input is: 25 the output is: 25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 Use Python, please.
19.16 LAB: Area of a triangle Using Heron's formula, you can calculate the area of a triangle if you know the lengths of all three sides. Given the length of each side of a triangle as input, calculate the area of the triangle using Heron's formula as follows: s = half of the triangle's perimeter area = the square root of s*(s-a)*(s-b)*(s-c), where a, b, and c are each sides of the triangle. Hint: Use the math function sqrt() for calculating the square root. Output the floating-point value of the area with two digits after the decimal point using the following statement once before all other cout statements:cout << fixed << setprecision(2); Ex: If the input for a, b, and c is: 3.0 4.0 5.0 the output is: Triangle area = 6.00 #include <iostream>#include <iomanip>#include <cmath>using namespace std; int main() { /* Type your code here. */ return 0;
change normal body temperature to 36.5–37.5 °C #include<iostream>using namespace std;int main(){ float temp;cout<<"Enter the body temperature in Celsius\n";cin>>temp;if (temp>=37){cout<<"The quarantine of the patient is required\n";cout<<"Enter the name of the patient\n";string patient;cin>>patient;cout<<"Where the passenger is from\n";string place;cin>>place;cout<<patient<<" from "<<place<<"is to be quarantined at Hospital"; }cout<<"Normal temperature\n";}
Can u debug this Program gets a store's department code and a sale transaction value // Output is a list of department codes, names, and total sales // Additionally, a grand total sales value is displayed start num dept num saleValue num NUM_DEPTS = 5 num total[NUM_DEPTS] string DEPT_NAME[NUM_DEPTS] = "Women's apparel", "Men's apparel", "Children's apparel", "Cosmetics", "Accessories", num grandTotal input dept, saleValue while not eof total[dept] = total[dept] + sale endwhile while dept < NUM_DEPTS output dept, DEPT_NAME[dept], total[dept] endwhile output "Grand total", grandTotal stop
# NumberFun.py # using multiple functions. # copy/paste this program to run it first, you are supposed to use Google Chrome as Internet Browser for this course. # 1. calculate sum of the first n natural numbers, e.g.:1,2,3,... def sumN(n): sumN = 0 for i in range(1,n+1): sumN = sumN + i return sumN # 2. calculate sum of the square of the first m natural numbers, e.g.:1,4,9,... ### After you define/write/complete the function sumMSquare(m), remove the # sign as below to ENABLE next line of code ####def sumMSquare(m):### YOUR TURN TO DEFINE/WRITE/COMPLETE function sumMSquare(m) as below, based on sumN(n) # 3. call two functions defined previously within main() function def main(): print("This program computes the total and total of squares of the first") print("N/M natural numbers.\n") n,m = input("Please enter a value for N and M: ").split(",") print("The total of the first", n, "natural numbers is", sumN(int(n)))### After you define/write/complete the function sumMSquare(m), remove…
Dry run the following code. You have to complete the iterations and fill the table: #include <iostream> using namespace std; int main(){int m = 10, n =10;int i,j;for(i=1,j=1;i<=m,j<=n;i=i+2,j=j+1){if((i+j) % 2 ==0){cout<<m*(i-1)+j;j=i+j;}else{cout<<n/(i+1)+j;j=i*j;}}cout<<end1;return 0;}
(Temperature Conversions) Write a program that converts integer Fahrenheit temperaturesfrom 0 to 212 degrees to floating-point Celsius temperatures with 3 digits of precision. Perform thecalculation using the formulacelsius = 5.0 / 9.0 * (fahrenheit - 32);The output should be printed in two right-justified columns of 10 characters each, and the Celsiustemperatures should be preceded by a sign for both positive and negative values.
Convert totalYears to millennia, decades, and years, finding the maximum number of millennia, then decades, then years. Ex: If the input is 9011, then the output is: Millennia: 9 Decades: 1 Years: 1 Note: A millennium has 1000 years. A decade has 10 years #include <iostream>using namespace std; int main() { int totalYears; int numMillennia; int numDecades; int numYears; cin >> totalYears; cout << "Millennia: " << numMillennia << endl; cout << "Decades: " << numDecades << endl; cout << "Years: " << numYears << endl; return 0;}