Interested in exploring the genetic pathways that lead to neurological issues, you want to see if recessive mutations which generate too many neurons (tm) in flies - which many causes autistic like symptoms are in the same gene as mutations that generate too few neurons (tf) - intellectual diabilities. You cross a true-breeding homozygous tm/tm fly to a homozygous too few neuron fly tf/tf. What phenotype in the progeny would tell these mutations are in different genes?
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Interested in exploring the genetic pathways that lead to neurological issues, you want to see if recessive mutations which generate too many neurons (tm) in flies - which many causes autistic like symptoms are in the same gene as mutations that generate too few neurons (tf) - intellectual diabilities. You cross a true-breeding homozygous tm/tm fly to a homozygous too few neuron fly tf/tf. What
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- You are working in the lab with strains of Drosophila that have either normal legs or abnormally short legs and you are studying the gene responsible. You know that normal legs are dominant to short legs. You come across a misplaced fly with normal legs, but you are not sure of his genetic background and you want to keep him in your experiments. (Without doing a molecular analysis), How could you figure out whether he was heterozygous or homozygous for the leg gene that you are studying? (Describe what you would do and how the results would answer the question.) What is the procedure you described above called?Our understanding of maternal effect genes has been greatly aided by their identification in experimental organisms such as Drosophila melanogaster and Caenorhabditis elegans. In experimental organisms with a short generation time, geneticists have successfully searched for mutant alleles that prevent the normal process of embryonic development. In many cases, the offspring die at early embryonic or larval stages. These are called maternal effect lethal alleles. How would a researcher identify a mutation that produced a recessive maternal effect lethal allele?A couple who are both heterozygous for an autosomal recessive mutation that is narrowly expressed and fully penetrant are planning on having three children. What is the probability that one their children will be normal (unaffected) and two children will have the recessive mutant phenotype? Show your work. Please answer this question using the Bayes’ Theorem
- An undergraduate researcher in your lab is studying mutations affecting the wings of Drosophila melanogaster. She has identified two mutant phenotypes of interest: bent wings (be), which are recessive to the wild-type straight wings (be+), and apterous (ap) mutants (which are wingless). The apallele is recessive to the wild-type allele (ap+), which allows wings to develop. If a homozygous bent-winged fly (which possesses the normal allele of apterous) is crossed with a homozygous wingless fly (which possesses the normal allele of bent wings), what phenotypic ratio would you expect to observe in the F2 generation of this cross? a) Please indicate the ratio, including the genotypes and phenotypes of all phenotypic classes. Phenotype: Genotype(s) corresponding to this phenotype Phenotypic ratio: (Be sure to NAME the classes in the ratio). B) Please NAME and DEFINE the type of gene interaction illustrated in this example.Suppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture) (ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Based on these data, does it appear that Protein B, when present and active, favors or inhibits PCD/Apoptosis?Briefly explain your reasoning. The answer should address both the paw and brain/skull data.There are two genetic disorders that result from mutation in imprinted genes: Prader-Willi syndrome, Angelman syndrome. Angelman syndrome results from deletion of UBE3A, which is a gene imprinted such that only the maternal copy is expressed. In the pedigree above, individual I-1 is heterozygous for a deletion of UBE3A and does not have Angelman syndrome. Individual I-2 is homozygous wild type for UBE3A. Which individuals in the pedigree are at risk for exhibiting Angelman syndrome, if any? (Who could potentially have the syndrome, based on what alleles it is possible for them to inherit and express?) Question 8 options: Only I-1 could have been at risk. If he does not have the syndrome, no one in the pedigree could. Only III-1 is at risk I-1, II-2, and III-1 are all at risk Only II-2 is at risk No one in the pedigree is at risk Both II-2 and III-1 are at…
- There are two genetic disorders that result from mutation in imprinted genes: Prader-Willi syndrome and Angelman syndrome. Prader-Willi syndrome results from deletion of region 15q11-q13, which in healthy individuals is a region imprinted such that only the paternal copy is expressed. In the pedigree above, individual I-1 is heterozygous for a deletion of region 15q11-q13 and does not have Prader-Willi syndrome. Individuals I-2 and II-1 are both homozygous wild type for the region. Which individuals in the pedigree might have Prader-Willi syndrome? (Who could potentially have the syndrome, based on what alleles it is possible for them to inherit and express?) Question 9 options: Only II-2 could have Prader-Willi syndrome III-1 could have Prader-Willi syndrome in the presented pedigree; II-2 could only have had it if she were male Both II-2 and III-1 could have Prader-Willi syndrome II-2 could have…In mammals, albinism is caused by an autosomal allele that interferes with skin pigment. Early one morning on your way to genetics class, you observe that two normally pigmented javelina parents have an albino piglet. What are the genotypes of the parents? _________________________________ What is the probability that their next five offspring will be albino? __________________________ What is the probability that 3 of the next 7 offspring will be normally colored?______________________ Describe the process by which you would test these normally colored offspring to see if they carried the albinism gene. What are the expected ratios from that test? You want to develop a strain of albino javelina for commercial use (the other really white meat). Describe how you would go about developing that strain starting with the 2 parents and the one albino offspring.How can you use this piece of information to help you explain to your friends what is the significance of mutations in the emergence of new genetic properties (alleles) that may result (or not) in new phenotypic characteristics? (Recall that not all SNPs affect phenotype.)
- Imagine that you caught a female albino mouse inyour kitchen and decided to keep it for a pet. A fewmonths later, while vacationing in Guam, you caughta male albino mouse and decided to take it home forsome interesting genetic experiments. You wonderwhether the two mice are both albino due to mutations in the same gene. What could you do to find outthe answer to this question? Assume that both mutations are recessive.. In 1932, H. J. Muller suggested a genetic test to determine whether a particular mutation whose phenotypiceffects are recessive to wild type is a null (amorphic)allele or is instead a hypomorphic allele of a gene.Muller’s test was to compare the phenotype of homozygotes for the recessive mutant alleles to the phenotype of a heterozygote in which one chromosomecarries the recessive mutation in question and thehomologous chromosome carries a deletion for aregion including the gene.In a study using Muller’s test, investigators examined two recessive, loss-of-function mutant alleles ofrugose named rg41 and rgγ3. The eye morphologiesdisplayed by flies of several genotypes are indicated inthe following table. Df(1)JC70 is a large deletion thatremoves rugose and several genes to either side of it.Genotype Eye surface Cone cells per ommatidiumwild type smooth 4rg41/rg41 mildly rough 2–3rg41/Df(1)JC70 moderately rough 1–2rg γ3/rg γ3 very rough 0–1rg γ3/Df(1)JC70 very rough 0–1a. Which allele…Star eye A peculiar eye condition known as "star” is manifested as a dominant gene in Drosophila. Its recessive allele R* produces the normal eye of wild type. The expression of R can be suppressed by the dominant allele of another locus, Ru-R. Ru-R*, as the recessive allele of the said locus, has no inhibitory effect on R*. When a normal-eyed male of genotype Ru-R Ru-R RR is crossed to a homozygous wild-type female of genotype Ru-R* Ru-R* R*R*, what phenotypic ratio is expected in the F2?