Answered: IO3. Ksp= 1.57x10^-9 How many…

IO3. Ksp= 1.57x10^-9 How many millimoles of Ba(NO3)2 are needed to completely react with NaIO3? 500 mmol 250 mmol 25 mmol 12.5 mmol What is the limiting reagent? NaIO3 Ba(NO3)2 Ba(IO3)2 NaNO

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.20QAP

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

100%

In order to form Ba(IO₃)₂, 500 mL of 0.5000 M Ba(NO₃)₂ was mixed with 500 mL of 0.0500 M NaIO₃.

Ksp= 1.57x10^-9

How many millimoles of Ba(NO₃)₂ are needed to completely react with NaIO₃?

500 mmol
250 mmol
25 mmol
12.5 mmol

What is the limiting reagent?
1. NaIO3
2. Ba(NO3)2
3. Ba(IO3)2
4. NaNO

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In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3. Ksp= 1.57x10^-9How many millimoles of Ba(NO3)2 are needed to completely react with NaIO3?What is the limiting reagent?What is the excess reagent?
In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3. Ksp= 1.57x10^-9 How many millimoles of Ba(NO3)2 are needed to completely react with NaIO3? 500 mmol 250 mmol 25 mmol 12.5 mmol What is the concentration of the excess reagent? 0.1125 M 0.3219 M 0.1195 M 0.2375 M What is the molar solubility of Ba(IO3)2 in this solution? 04x10^-5 M 07x10^-5 M 15x10^-5 M 30x10^-5 M
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