Write clearly so I can see 8. (12) An analyst measured the concentration of acid in a solution using two differentindicators. His results were as follows:Mean [HCI] F stand. Dev.0.02467 F 0.00450.02407 † 0.0032# measurementsIndicator A:18Indicator B:12Is the difference between the two indicators significant at the 95% confidence level?15etvMacBook Air20F3DIDDF4F5F6F7F8F9F1023$%&*34789EYGKI L Degrees of freedom509095989999.5 99.91.0000.8160.7656.314 12.706 31.8212.9202.35363.656 127.321 636.5789.92514.3036.96514.08931.5983,1822.7762.57112.9244.5413.7473.36535.8417.4532.1322,0151.9431.8951.8605.5984.6044.0328.6106.86940.7410.7270.7184.7736.2.4473.1433.7074.3175.9590.7112.3652.9983.5004.0295.4080.7060.70382.3062.8963.3553.8325.04191.8332.2622.8213.2503.6904.781100.7001.8122.2282.7643.1693.5814.5870.6910.6871.7531.7251.7081.697152.1312.6022.9473.2524.073202.0862.5282.8453.1533.850250.6842.0602.4852.7873.0783.725300.6830.6810.6790.6772.0422.4572.7503.0303.646401.6841.6711.6581.6452.0212.0001.9802.4232.7042.6602.9713.551602,3902.3582.3262.9153.4603.3731202.6172.5762.8600.674.1.9602.8073.291NOTE: In calculating confidence intervals, a may be substituted for s in Equation 4-6 if you have a great deal ofexperience with a particular method and have therefore determined its "true" population standard deviation. If o isused instead ofs, the value of t to use in Equation 4-6 comes from the bottom row of Table 4-2.Next5étvMacBook AirF5DIF6F7F8F9F10F11F12&*6.%3DY{}JBNM+ ||* CO

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Answered: Is the difference between the two…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Independent random samples of patients who had received knee and hip replacement were asked to assess the quality of service on a scale from 1 (low) to 7 (high). For a sample of 83 knee patients, the mean rating was 6.543 and the sample standard deviation was 0.649. For a sample of 54 hip patients, the mean rating was 6.733 and the sample standard deviation was 0.425. Test, against a two-sided alternative, the null hypothesis that the population mean ratings for these two types of patients are the same.
In a study of morphological variation in natural populations of fruit fly, it was reported that the mean wing length of 16 females, collected in a certain area, was 4.653 mm with s = 0.012 mm; and the mean wing length of 11 females, collected in a second area, was 4.274 mm with s = 0.02. Let the distribution of the wing length be normal, find a 98% confidence interval on the ratio of the two populations’ standard deviations.
1 Suppose that the average time spent per day with digital media several years ago was 3 hours and 22 minutes. For last year, a random sample of 20 adults in a certain region spent the numbers of hours per day with digital media given in the accompanying table. Preliminary data analyses indicate that the t-interval procedure can reasonably be applied. Find and interpret a 90% confidence interval for last year's mean time spent per day with digital media by adults of the region. (Note: x=5.88hr and s=2.27hr.) The 90% confidence interval is from ( ? ) hour(s) to ( ? )hour(s). Interpret the 90% confidence interval. Select all that apply. A. There is a 90% chance that the mean amount of time spent per day on digital media last year by all adults in the region is between the interval's bounds. B.With 90% confidence, the mean amount of time spent per day on digital media last year by all adults in the region is between the interval's bounds. C.90% of all…
A large school district found that 88 of 100 randomly selected students at East High School had internet access at home . A separate random sample from West High showed 79 of 100 students had internet access at home Administrators used those results to make a 90\% confidence interval to estimate the difference between the proportion of students at each school who have internet access at home (p Z -p W ) . resulting Interval was approximately 0.09 plus/minus 0.086 . They want to this interval to test H 0 * p 0 =p w versus H k :p k ne pw at the alpha = 0.10sisnl significance levelAssume that all conditions for Inferance been mel Based on the Intervalwhat do we know about the corresponding P-value and condusion at the alpha = 0.10 level of significance?
. A taxi company has been using Brand A tires, and the distribution of kilometers to wear-out has been found to be approximately normal with mean =114,000 and σ = 11,600. Now it tries 12 tires of Brand B and finds a sample mean 117,200. Test at the 5% level of significance to see whether there is a significant difference (positive or negative) in kilometers to wear-out between Brand A and Brand B. In the problem above, if the true kilometers to wear-out is 114,000, what is the 95% confidence interval for sample means? First show how to get the critical z values.
The tensile strengths of two types of materials were investigated by collecting 16 samples of each material (totally 32 samples).The sample mean for material 1 was 423.08 (psi), and for material 2 was 424.7 (psi). The samplestandard deviation of the difference in tensile strengths was sD = 2.8 (psi). Is there sufficientevidence to conclude that two types of materials have the same tensile strength? Formulate andtest the appropriate null H0 and alternative hypotheses H1 to verify the claim at level α = 0.01
The mean ± 1 SD of calcium intake (in mg) among 25 females, 12-14 years of age, below the poverty level is 6.56 ± 0.64. Similarly, the mean ± 1 SD of calcium intake among 40 females, 12-14 years of age, above the poverty level is 6.80 ± 0.76. Do we have sufficient evidence to conclude that the mean intake of calcium among females below the poverty level is significantly lower than the calcium intake of females above the poverty level? State the null and alternative hypothesis in mathematical notation Ho: Ha: What is the level of significance to be used? What is the appropriate test statistic? Why? What is the critical region? Compute for the test statistic. Show all your computations below. What is the statistical decision? What is your basis for such decision? How would you conclude your findings? Be specific.
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Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield (bar x) x=99.3, (bar y) y=99.5, r=0.943, P-value=0.000, and (^ over y) y=−5.29+1.06x, where x represents the IQ score of the younger child. Find the best-predicted value of (^ over y) y given that the younger child has an IQ of108?Use a significance level of 0.05. The critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r n α=0.05 α=0.01 NOTE: To test H0: ρ=0 against H1: ρ≠0, reject H0 if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 5 0.878 0.959 6 0.811 0.917 7 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590…
In the year 2017, the mean and standard deviation for the quality grade point average of the first-year students in a basic statistics course is found to be 2.95 and 0.53. If 38 undergraduates are randomly selected, find the 95% confidence interval for the mean of the entire group. Within the same year, if another group of 38 students were sampled and resulted with a mean of 2.87, test the hypothesis that the sample mean is different from the population mean at a 5% level of significance.

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