is there a doctor in the house? A market research firm reported the mean annual earnings of all familypractitioners in the United States was $178,258 . A random sample of 47 family practitioners in Los Angeles hadmean earnings of x $192,890 with a standard deviation of $43,117 . Do the data provide sufficient evidenceto conclude that the mean salary for family practitioners in Los Angeles is greater than the national average? Use thea 0.01 level of significance and the p-value method with theCritical Values for the Student's t Distribution Table.(a) State the appropriate null and alternate hypotheses.(b) Compute the value of the test statistic.(c) State a conclusion.

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Asked Nov 5, 2019
is there a doctor in the house? A market research firm reported the mean annual earnings of all family
practitioners in the United States was $178,258 . A random sample of 47 family practitioners in Los Angeles had
mean earnings of x $192,890 with a standard deviation of $43,117 . Do the data provide sufficient evidence
to conclude that the mean salary for family practitioners in Los Angeles is greater than the national average? Use the
a 0.01 level of significance and the p-value method with the
Critical Values for the Student's t Distribution Table.
(a) State the appropriate null and alternate hypotheses.
(b) Compute the value of the test statistic.
(c) State a conclusion.
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is there a doctor in the house? A market research firm reported the mean annual earnings of all family practitioners in the United States was $178,258 . A random sample of 47 family practitioners in Los Angeles had mean earnings of x $192,890 with a standard deviation of $43,117 . Do the data provide sufficient evidence to conclude that the mean salary for family practitioners in Los Angeles is greater than the national average? Use the a 0.01 level of significance and the p-value method with the Critical Values for the Student's t Distribution Table. (a) State the appropriate null and alternate hypotheses. (b) Compute the value of the test statistic. (c) State a conclusion.

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Expert Answer

Step 1

The provided information are:

Sample size (n) 47
Sample mean ()192890
Sample standard deviation (s) = 43117
Hypothesized population mean (4) =178258
a 0.01
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Sample size (n) 47 Sample mean ()192890 Sample standard deviation (s) = 43117 Hypothesized population mean (4) =178258 a 0.01

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Step 2

(a)

The null and alternative hypotheses are:

H 178258
H 178258
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H 178258 H 178258

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Step 3

The alternative hypothesis suggests that the test is right tailed.

(b)

Here, the population standard deviation is unknown, so ...

S
192890-178258
43117
47
= 2.327
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S 192890-178258 43117 47 = 2.327

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