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It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020

It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter19: Nuclear Chemistry
Section: Chapter Questions
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relate to the following scenario: It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 103 m3.
Transcribed Image Text:relate to the following scenario: It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 103 m3.
It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed %3D basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020
Transcribed Image Text:It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed %3D basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020
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