It is well known that the optical fiber works based on internal total reflection. In Figure 3, assuming ni is 1.6 and n2 is 1.5. A beam of light is incident into the fiber from air with angle 61. Try to calculate the range for 01 to make sure the light can propagate in the fiber with total reflection. n2 AIR P ni n2 Figure 3

It is well known that the optical fiber works based on internal total reflection. In Figure 3, assuming ni is 1.6 and n2 is 1.5. A beam of light is incident into the fiber from air with angle 61. Try to calculate the range for 01 to make sure the light can propagate in the fiber with total reflection. n2 AIR P ni n2 Figure 3

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter38: Refraction And Images Formed By Refraction

Section: Chapter Questions

Problem 92PQ

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In the figure, light enters a 90° triangular prism at point A with incident angle θ, and then some of it refracts at point B with an angle of refraction of 90°. (a) What is the index of refraction of the prism in terms of θ? (b) What, numerically, is the maximum value that the index of refraction can have? (c) Does light emerge at B if the incident angle at A is (i) increased slightly and (ii) decreased slightly? Hint: sin2θ + cos2θ = 1. Answer: √(1+ sin2θ), 1.41, emerges into air, internally reflected
Consider a ray of light that propagates from air ( n=1 ) to any one of the materials listed below. Assuming that the ray strikes the interface with any of the listed materials always at the same angle θ1 , in which material will the direction of propagation of the ray change the most due to refraction? What is the critical angle θcrit for light propagating from a material with index of refraction of 1.50 to a material with index of refraction of 1.00?
Light rays fall normally on the vertical surface of a glass prism (n = 1.6) as shown in Figure. 1)What is the largest value of θθ such that the ray is totally internally reflected at the slanted face? (Express your answer to three significant figures.) 2)Repeat the calculation if the prism is immersed in water with n=1.33. (Express your answer to three significant figures.)
Although we do not prove it here, the minimum angle of deviation δmin for a prism occurs when the angle of incidence θ1 is such that the refracted ray inside the prism makes the same angle with the normal to the two prism faces1 as shown. Obtain an expression for the index of refraction of the prism material in terms of the minimum angle of deviation and the apex angle Φ.
An optical fiber has an index of refraction n and diameter d. It is surrounded by vacuum. Light is sent into the fiber along its axis as shown. (a) Find the smallest outside radius Rmin permitted for a bend in the fiber if no light is to escape. (b) What If? What result does part (a) predict as d approaches zero? Is this behavior reasonable? Explain. (c) As n increases? (d) As n approaches 1? (e) Evaluate Rmin assuming the fiber diameter is 100 mm and its index of refraction is 1.40.
Consider a horizontal interface between air above and glass of index of refraction 1.55 below. (a) Draw a light ray incident from the air at angle of incidence 30.0°. Determine the angles of the reflected and refracted rays and show them on the diagram. (b) What If? Now suppose the light ray is incident from the glass at an angle of 30.0°. Determine the angles of the reflected and refracted rays and show all three rays on a new diagram. (c) For rays incident from the air onto the air–glass surface, determine and tabulate the angles of reflection and refraction for all the angles of incidence at 10.0° intervals from 0° to 90.0°. (d) Do the same for light rays coming up to the interface through the glass.
For the picture below, determine the displacement of the light ray when the incident angle is 25°. The glass slab (? = 1.4) is 0.050 m thick
A block of acrylic has a wedge-shaped cavity filled with air, where the opening angle θ is 38°. If a light ray travelling straight up is incident from the cavity into the block as shown in the figure, what angle does the refracted light ray make with the indicated normal? Enter -1 if the light ray does not exit the cavity at the indiciated point because of total internal reflection.
A fish is swimming 3.25 meters below the surface of the lake (n=1.33), as the fisherman approaches in his boat. What is the critical angle for light leaving the fish to undergo total internal reflection? (Give your answer in degrees.) How close does the fisherman need to get to see the fish (labeled r in the image)? Ignore the fisherman's height above the water for this calculation. Give your answer in meters.
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