It's been close to 6 years since I took Calculus 1. Can someone explain in detail how to evaluate the Indefinite Intergal below?[9,1]  sqrt(2x+7) dxI let u = 2x+7then solved for 'x' as follows: 2(9)+7 = 9then set du/dx = 2x+7, which I rewrote as dx=1/2 duAfter this step I'm lost as to what I have to do next.

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Asked Aug 28, 2019
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It's been close to 6 years since I took Calculus 1. Can someone explain in detail how to evaluate the Indefinite Intergal below?

[9,1]  sqrt(2x+7) dx

I let u = 2x+7

then solved for 'x' as follows: 2(9)+7 = 9

then set du/dx = 2x+7, which I rewrote as dx=1/2 du

After this step I'm lost as to what I have to do next.

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Expert Answer

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Step 1

We need to evaluate the definite integral,

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9 V2x7 dx I 1

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Step 2

We can first solve the integral as follows,

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V2x7 dx 2х + 7, Substitute u So, du 2dx V2x7 dx du 2 _ We know that, un+1 (Power rule) u"du n 1 1 in the above formula, 2 using we get _ 3 3 Vu 1 u2 u2 du 2 3 2 3 2 2x7 in the above expression give us, using 3 3 (2x 7) C u2 3 3

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Step 3

So, we calculate the defi...

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319 9 |(2x7)2 V2x7 dx 3 3 3 ž (2(9)7) (2(1) 7) 3 3 98 3

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Math

Calculus

Integration

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