Question

Asked Aug 28, 2019

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It's been close to 6 years since I took Calculus 1. Can someone explain in detail how to evaluate the Indefinite Intergal below?

[9,1] sqrt(2x+7) dx

I let u = 2x+7

then solved for 'x' as follows: 2(9)+7 = 9

then set du/dx = 2x+7, which I rewrote as dx=1/2 du

After this step I'm lost as to what I have to do next.

1 Rating

Step 1

We need to evaluate the definite integral,

Step 2

We can first solve the integral as follows,

Step 3

So, we calculate the defi...

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