11-12 how to solve?! IV) For the voltage waveform shown below. If the voltage is in volts and the time is inmilliseconds, answer questions 1-12.2.-3t(ms)11) The RMS value of the voltage waveform is .. V:a) 2.6e) 1.47sin(wt)b) 0.4702.94e) 2.31) 1.63h) None of the aboveN The average real power absorbed by an impedance of Z 2-j5 2 when this voltage sourceiapplied acros it s W.a)0.181048b) 0.24D132e) 0.96R) 4.80d) 0.77h) None of the above

IV) For the voltage waveform shown below. If the voltage is in volts and the time is in milliseconds, answer questions 1-12. 2. 2. -3t (ms) 11) The RMS value of the voltage waveform is .. V: a) 2.6 e) 1.47sintwt) b) 0.47 e) 2.31 02.94 ) 1.63 h) None of the above The averge real power absorbed by an impedance of Z 2-j5 2 when this voltage source is applied across it is W. a)018 T048 b) 0.24 D1.32 e) 0.96 ) 4.80 d) 0.77 h) None of the above

IV) For the voltage waveform shown below. If the voltage is in volts and the time is in milliseconds, answer questions 1-12. 2. 2. -3t (ms) 11) The RMS value of the voltage waveform is .. V: a) 2.6 e) 1.47sintwt) b) 0.47 e) 2.31 02.94 ) 1.63 h) None of the above The averge real power absorbed by an impedance of Z 2-j5 2 when this voltage source is applied across it is W. a)018 T048 b) 0.24 D1.32 e) 0.96 ) 4.80 d) 0.77 h) None of the above

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.2MCQ: If the rms phasor of a voltage is given by V=12060 volts, then the corresponding v(t) is given by...

See similar textbooks

Similar questions

Derive the formula for Average Power, Pavg = VI cosθ watts, where V is the root-mean-square (rms) voltage in volts, I is the root-mean-square (rms) current in ampere, and cosθ is the power factor. For the derivation, use the sinusoidal voltage and current equations. The angle between the voltge and current is angle θ
calculate the rms value in v of this signal shown below:
derive the RMS formula for the following a.) b.)
The average power consumed by a typical kettle with a heating element that has a pure resistance of 10Ω is 1200W. Calculate: a) the RMS current drawn by the kettle b) the peak value of the current through the element
compute the RMS value for the current waveform and ys them to determine average power supplied to the resistor....
Calculate the RMS value of the following function
A voltage given by v(t) = 311 cos (311 pi t) V is applied to a 50-ohm resistance. (a.) Sketch v(t) to scale versus time. (b.) Determine the rms value of the voltage and the average power delivered to the resistance. (c.)Determine the power as a function of time and sketch to scale.
A dc voltage equal to Vdc V is applied to a resistor of R Ω. Asinusoidal voltage equal to vs V is also applied to a resistor of R Ω.Show that the dc voltage will deliver the same amount of energy in Tseconds (where T is the period of the sinusoidal voltage) as thesinusoidal voltage provided Vdc equals the rms value of vs. (Hint:Equate the two expressions for the energy delivered to the resistor.)
1) the RMS value of the current is? /2) the peak value of the voltage is?/3) the value of the reactive power is?
Consider the following equation: v (t) = 110 sin(78.5 t) Calculate: Frequency (f) = ? Time period (T) = ? Peak Voltage (Vp) = ? Average voltage (VAVG) = ? RMS voltage (VRMS) = ? Sketch the labelled waveform showing Peak voltage, full cycle and half-cycle times.
Determine the rms (or effective) value ofv(t) = VDC + vAC = 50 + 70.7 cos(377t) V
1. Determine the RMS values of voltage and current, and the total power absorbed by the circuit element