Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 36 students, she finds 2 who eat cauliflower. Obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. C Construct and interpret the 95% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) OA. The proportion of students who eat cauliflower on Jane's campus is between and 95% of the time. OB. There is a 95% chance that the proportion of students who eat cauliflower in Jane's sample is between OC. There is a 95% chance that the proportion of students who eat cauliflower on Jane's campus is between OD. One is 95% confident that the proportion of students who eat cauliflower on Jane's campus is between and and and

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 36 students, she finds 2 who eat cauliflower. Obtain and interpret a 95%
confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.
Click the icon to view Agresti and Coull's method.
Construct and interpret the 95% confidence interval. Select the correct choice below and fill in the answer boxes within your choice.
(Round to three decimal places as needed.)
O A. The proportion of students who eat cauliflower on Jane's campus is between and 95% of the time.
O B. There is a 95% chance that the proportion of students who eat cauliflower in Jane's sample is between
OC. There is a 95% chance that the proportion of students who eat cauliflower on Jane's campus is between
OD. One is 95% confident that the proportion of students who eat cauliflower on Jane's campus is between
and
and
and
Transcribed Image Text:Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 36 students, she finds 2 who eat cauliflower. Obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. Construct and interpret the 95% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) O A. The proportion of students who eat cauliflower on Jane's campus is between and 95% of the time. O B. There is a 95% chance that the proportion of students who eat cauliflower in Jane's sample is between OC. There is a 95% chance that the proportion of students who eat cauliflower on Jane's campus is between OD. One is 95% confident that the proportion of students who eat cauliflower on Jane's campus is between and and and
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