JAVA Write a function to implement bottom-up minimal exchange algorithm for generating permutation of {1, 2, 3, 4, … , n}. Call your function from within a main program. Submit code and a sample output for the case n = 4. You may also submit a hand calculated version for (n = 4) if you rather not write a program. Please explain step-by-step.
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JAVA Write a function to implement bottom-up minimal exchange
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- a) Implement a function start( ) that takes as input a positive number a, rounds its logarithm base 4 to the nearest integer n, and returns the value of 1.0 x 2^n.Write a function triple_riffle_repeat(mylist,n) which takes as input a list (again with length a multiple of 3) and outputs the result of doing a 3-way riffle shufffle n times Write a function period(m) which takes as input a number m (which we will always take as a multiple of 3) and outputs the smallest positive integer n so that triple_riffle_repeat(list(range(m)),n) == list(range(m)) Discuss, with evidence, the outputs of your function period for different values of m, writing your answer as a comment.(Program) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters, such as zerocount, onecount, twocount, and so forth, to 0. Then generate a large number of pseudorandom integers between 0 and 9. Each time 0 occurs, increment zerocount; when 1 occurs, increment onecount; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of time they occurred.
- Write pseudocode for a function Det-Quicksort(A, p, r) that receives array A[1..n], and indices p and r. The function should sort the subarray A[p..r] recursively (meaning you should call itself). You can also use a function LinearSearch(A, p, r, v) that searches subarray A[p..r] for an element of value v and return its index (in case it exists) in O(r − p) time. (Just to give you something to compare to, the solution has 8 lines.)Write a function/ program that produces the following: int findDifference(const string a1[], int n1, const string a2[], int n2); Return the position of the first corresponding elements of a1 and a2 that are not equal. n1 is the number of interesting elements in a1, and n2 is the number of interesting elements in a2. If the arrays are equal up to the point where one or both runs out, return the smaller of n1 and n2. Notwithstanding each function's behavior described below, all functions that return an int must return −1 if they are passed any bad arguments (e.g. a negative array size, or a position that would require looking at the contents of an element past the last element we're interested in). Unless otherwise noted, passing 0 to the function as the array size is not itself an error; it merely indicates the function should examine no elements of the array. Here's an example: string cast[5] = { "samwell", "jon", "margaery", "daenerys", "tyrion" }; string roles[4] = { "samwell",…solve the problem in java:Consider the are n=2 subjects and needed =[4,5]answered questions, to pass.The student has answered =[2,4] questions in the two subjects so far, and can answer another q=1 questions across all subjects combined. The best outcome is to answer an additional question in the second subject on order to pass it, as 2 more answers required to pass the first subject. the max number of subject s that can be passed is 1. the function must return an integer that can represent the max number of subjects that can be passed. public static int maxNumsub(List <Integer> answered, List<Integer> needed, int q){//write code here}
- Implement a function (Java or pseudocode) that will accept a mathematical expression which containssquare brackets, curly brackets and normal brackets (i.e. “[ …]”, “{ …}” and “( … )”) as the input andwould return whether the expression has matching brackets or not. The input expression will be given asa String array where each element in the array is a bracket (one of “[”, “]”, “{”, “}”, “(”, “)”) number ora mathematical operator. It should return true if expression has matching brackets and false otherwiseUsing recursion, write a Python function def before(k,A) which takes an integer k and an array A of integers as inputs and returns a new array consisting of all the integers in A which come before the last occurrence of k in A, in the same order they are in A. For example, if A is [1,2,3,6,7,2,3,4] then before(3,A) will return [1,2,3,6,7,2]. If k does not occur in A, the function should return None.write java codes to do the following: Write a recursive function to check if an integer array is negative symmetric, for example, an array of 10, 20, 30, 90, -30, -20, -10 is considered as negative symmetric, while an array of 10, 20, 30, 90, 30, 20, 10 is not considered as negative symmetric. public static boolean checkArraySym(int [ ] A, int first, int last) that receives an array A, first index, last index and checks if the array is negative symmetric
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