K-Maps & Gate-level Minimization Given the following Boolean expression: F = AB' + AD + AC' + A'CD 1. Obtain the KMAP to get minterms and maxterms 2. What are the Minterms? (Example: m0, m1) 3. What are the Maxterms? (Example: M0, M1) 4. Provide the Simplified Boolean Function using KMAP (Example: F= A)
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- Q1: Design and implement an asynchronous counter that counts from 0000 up to 1100 (modulus 13). Use OR gate, and show in the drawing how the OR gate is connected to truncate the state 1101.A 12-bit D/A converter has VREF = 5.12 V. What is the output voltage for a binary input code of (101010101010)? What is VLSB? What is the size of the MSB?A. Write a Verilog HDL code for Verilog code for a for 6-bit unsigned up counter B. Write test bench code of the circuit in the figure: DỊ40) 5-bit Full Adder 5-bit 5-bit Up - Counter DFF Ck
- Design a combinational circuit that takes 3-bit pattern as input and outputs binary code of bit position of the first 1' in the pattern reading from MSB (2nd position) to LSB (0th position).An additional output variable V is required along with binary code to indicate that the binary code is valid or note i.e., if the input pattern is '000' then the output V should be '0' to indicate that the binary code is not indicating the bit position of first 1' and we don't care about the binary code if V = 0. Design the required circuit using dual 4x1 MUXS and minimum additional logic.Available resources along with dual 4x1 MUXS are NOT gates, 2-input(AND, OR, NAND, NOR) gates.- The proportional distribution of A, B, C, D signals is given in the table as a percentage. It “logic 1” when the signals are accepted as active, “logic 0” when they are accepted as passive. takes. - When the proportional sum of active signals is over 50%, its output is "logic1", When we accept "logic 0" when it is below 50%, the output in the table Find the values. - Create an X function based on the logic values you find. Simplify the created X function. - Design the simplified function with NAND and NOR gates. - Set up the circuits you designed with NAND and NOR gates and observe the outputs. Show the output values by drawing a table, applying all possibilities to the input values.- The proportional distribution of A, B, C, D signals is given in the table as a percentage. It “logic 1” when the signals are accepted as active, “logic 0” when they are accepted as passive. takes. - When the proportional sum of active signals is over 50%, its output is "logic1", When we accept "logic 0" when it is below 50%, the output in the table Find the values. - Create an X function based on the logic values you find. Simplify the created X function. - Design the simplified function with NAND and NOR gates.
- parity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.DFF circuit that adds the one-bit numbers a and b in series. Design according to the Mealy model a)state diagram b)state table c)simplification with Karnaugh mapsDraw the schematic for a simple circuit that gives O/P according to AND gate logic. Determine “V0 ” for when both inputs are at level ‘1’& level ‘0’ and associated currents I.
- Q#01: The schematic shown in figure below is for Divide_by_11, a frequency divider, that divides clk by 11 and asserts its output for one cycle. The unit consists of a chain toggle-type flip-flops with additional logic to form an output pulse every 11th pulse of clk. The asynchronous signal rst is active-low and drives Q to 1. Develop and verify a model of Divide_by_11. Vcc 20LSB Q2 03MSB clk clk clk clk clk rst rst rst rst wl w2 clk QB cik_by_11 rst rstDesign a circuit that adds two 4-digit BCD numbers and finds the result as BCD, using 7483 (integrated circuits) and the necessary gates. (Note : You can see ‘What is 7483?’ from images.7. A certain TTL. gate has lat -20 A, la 01 mA, kan 04 mA and ke4 mA. Determine the input and ourput loading in the HIGH and LOw states in terms of UL. When the I UL (LOW state)-1.6 mA and I UL (HIGH state)40 A.