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KE gained by one electron (e) (Ecot) = (1.602x10 C) (9.37 V) CV (three significant digits). Note: one coulomb volt is equivalent to one joule; 1 CV = 1J.

KE gained by one electron (e) (Ecot) = (1.602x10 C) (9.37 V) CV (three significant digits). Note: one coulomb volt is equivalent to one joule; 1 CV = 1J.

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability
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If this energy is transferred to the atoms in the cathode and cause excessive heating and possible explosion. We call this a "short circuit." You prevent this by by allowing the electrons to pass through an electrical resistor, something like a light bulb, a motor, or a heater to use up the energy before the electrons make it to the cathode. If the heater were dipped in water, it would be enough to heat g of water from room temperature (25°C) to its boiling point (100°C). The energy is also enough to turn a motor in order to lift a kg object to a height of one meter; the work (in Joules) needed to lift an object to a height h is mgh, where m is the mass in kg, g is the acceleration due to gravity (9.80 m/s2), and h is in meters
Transcribed Image Text:If this energy is transferred to the atoms in the cathode and cause excessive heating and possible explosion. We call this a "short circuit." You prevent this by by allowing the electrons to pass through an electrical resistor, something like a light bulb, a motor, or a heater to use up the energy before the electrons make it to the cathode. If the heater were dipped in water, it would be enough to heat g of water from room temperature (25°C) to its boiling point (100°C). The energy is also enough to turn a motor in order to lift a kg object to a height of one meter; the work (in Joules) needed to lift an object to a height h is mgh, where m is the mass in kg, g is the acceleration due to gravity (9.80 m/s2), and h is in meters
KE gained by one electron (e) (E)= (1.602x10 C) (9.37 V) CV (three significant digits). Note: one coulomb volt is equivalent to one joule; 1 CV = 1J. What would be the total kinetic energy gained by a mole of electrons? First, let us calculate the charge of one mole of electrons; this is called Faraday's constant. We just multiply the charge one electron by Avogadro's number (NA = 6.022x103 mol '). F= (N (e) = C mol (three significant digits) KE gained by of one mole of electrons = NA (e) (Ece) Or (F)(Ec) J/mol (three significant digits) The kinetic energy that would be gained by n moles of electrons is (n)(FXEc«t}. A typical 9-V battery can put out a current of 0.58 A. One ampere (A) is equivalent a Coulomb per second. How much KE will be gained by electrons in one minute? First we calculate n, the moles of electrons in one minute. n= [(0.58 C/s) divided by (96500 C/mol) | times (60 seconds] = mol KE (n)(F)(E) J(three significant digits)
Transcribed Image Text:KE gained by one electron (e) (E)= (1.602x10 C) (9.37 V) CV (three significant digits). Note: one coulomb volt is equivalent to one joule; 1 CV = 1J. What would be the total kinetic energy gained by a mole of electrons? First, let us calculate the charge of one mole of electrons; this is called Faraday's constant. We just multiply the charge one electron by Avogadro's number (NA = 6.022x103 mol '). F= (N (e) = C mol (three significant digits) KE gained by of one mole of electrons = NA (e) (Ece) Or (F)(Ec) J/mol (three significant digits) The kinetic energy that would be gained by n moles of electrons is (n)(FXEc«t}. A typical 9-V battery can put out a current of 0.58 A. One ampere (A) is equivalent a Coulomb per second. How much KE will be gained by electrons in one minute? First we calculate n, the moles of electrons in one minute. n= [(0.58 C/s) divided by (96500 C/mol) | times (60 seconds] = mol KE (n)(F)(E) J(three significant digits)
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