- kel - ere k > 0 andcz 0. In Section 3.1 we saw that in the case c=o the linear differential equation dP/dt = kP is a mathematical model of a population P(t) that exhibits unbounded growth over the infinite time interval [0, c0), that is. )- co as t- 0o. See Example 1 in that section. (a) Suppose for c 0.01 that the nonlinear differential equation = kp1.01 k > 0, is a mathematical model for a population of small animals, where time t is measured in months. Solve the differential equation subject to the initial condition P(0) = 10 and the fact that the animal population has doubled in 8 months. (Round the coefficient of t to six decimal places.) P(t) = (b) The differential equation in part (a) is called a doomsday equation because the population P(t) exhibits unbounded growth over a finite time interval (0, T), that is, there is some time T such that P(t) - co as t-T. Find (Round your answer to the nearest month.) T= months (c) From part (a), what is P(70)? P(140)? (Round your answers to the nearest whole number.) P(70) = P(140) =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Question
Consider the differential equation
dP -
= kpl +c
dt
where k > 0 and c 2 0. In Section 3.1 we saw that in the case c = 0 the linear differential equation dP/dt = kP is a mathematical model of a population P(t) that exhibits unbounded growth over the infinite time interval [0, co0), that is,
P(t) - c0 as t - co. See Example 1 in that section.
(a) Suppose for c = 0.01 that the nonlinear differential equation
= kp1.01, k > o,
is a mathematical model for a population of small animals, where time t is measured in months. Solve the differential equation subject to the initial condition P(0) = 10 and the fact that the animal population has doubled in 8
months. (Round the coefficient of t to six decimal places.)
P(t) =
(b) The differential equation in part (a) is called a doomsday equation because the population P(t) exhibits unbounded growth over a finite time interval (0, T), that is, there is some time T such that P(t) – co ast-T. Find T.
(Round your answer to the nearest month.)
T =
months
(c) From part (a), what is P(70)? P(140)? (Round your answers to the nearest whole number.)
P(70) =
P(140) =
Transcribed Image Text:Consider the differential equation dP - = kpl +c dt where k > 0 and c 2 0. In Section 3.1 we saw that in the case c = 0 the linear differential equation dP/dt = kP is a mathematical model of a population P(t) that exhibits unbounded growth over the infinite time interval [0, co0), that is, P(t) - c0 as t - co. See Example 1 in that section. (a) Suppose for c = 0.01 that the nonlinear differential equation = kp1.01, k > o, is a mathematical model for a population of small animals, where time t is measured in months. Solve the differential equation subject to the initial condition P(0) = 10 and the fact that the animal population has doubled in 8 months. (Round the coefficient of t to six decimal places.) P(t) = (b) The differential equation in part (a) is called a doomsday equation because the population P(t) exhibits unbounded growth over a finite time interval (0, T), that is, there is some time T such that P(t) – co ast-T. Find T. (Round your answer to the nearest month.) T = months (c) From part (a), what is P(70)? P(140)? (Round your answers to the nearest whole number.) P(70) = P(140) =
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