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kg block is attachod toapring of force cotant 300 N in Fig The block is pulled S cm to the right of equil m d eeleed m . Answer Q11 and Q12: Qi1. The speed of the block as it pases through quilirium if the horinontal surface is frictionless a0.87 m/s b. 1.0 m/s e15 ms 4.20 ms Q12. The speed of the block as it passes throngh equilibeim when the coefficient of friction between block and surface is 04. a 0,77 m/s b. 0.88 m's e.0.59 m/s d. 188 mis Q13. The varying force depend on x is given by F(x)-Ox+2)N, where x in meter d to move it from x-2 m to x-3 m. The work done by this force on a bah a. 723 body b. 841

kg block is attachod toapring of force cotant 300 N in Fig The block is pulled S cm to the right of equil m d eeleed m . Answer Q11 and Q12: Qi1. The speed of the block as it pases through quilirium if the horinontal surface is frictionless a0.87 m/s b. 1.0 m/s e15 ms 4.20 ms Q12. The speed of the block as it passes throngh equilibeim when the coefficient of friction between block and surface is 04. a 0,77 m/s b. 0.88 m's e.0.59 m/s d. 188 mis Q13. The varying force depend on x is given by F(x)-Ox+2)N, where x in meter d to move it from x-2 m to x-3 m. The work done by this force on a bah a. 723 body b. 841

University Physics Volume 1
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 9.1CYU: Check Your Understanding The U.S. Air Force uses “10gs” (an acceleration equal to 109.8m/s2 ) as the...
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Al kg block is attached to a Noring of force constant 300 N a in Figure The block is pulled 5 cm to the right of equilibriam and seleased from ret. Answer Q11 and Q12: Q11. The speed of the block as it passes through cquilibrium if the horinontal surface is frictionless: a. 0.87 m/s Q12. The speed of the block as it passes through equilitrium when the cocfficient of friction between block and surface is 0.4, a. 0,77 m/s b. 1.0 m/s e1.5 m/s 4.20 ms b. 0.88 m/s c.0.59 m/s d. 1.88 m/s Q13. The varying force depend on x is given by F(x) - (3x+2) N, where x in meter nd t ona body to move it from x-2m to x-3 m. The work done by this force on a body is: a. 72J b. 84J c. 603 Q14. The expression of Newton's second law is: a. EF = ma 4. 211 b. EP = c. Er = la d. All of them d. (a +b) Q15. A 2.0-kg ball with an initial velocity of 4i m/s collides with a wall and rebounds witha velocity of -4i m/s. What is the impulse exerted on the ball by the wall? a.-16iNs b. -12INS C. -18INS d.-24 INs Q16. Three carts of masses mi=4 kg, m2 -10 kg and my =3 kg move on a frictionless, horizontal track with spceds of vi=4 m/s to the right, V2 =3 m/s to the right, and vs -5 m/s to the left as shown in Figure. Velcro couplers make the carts stick together after colliding. The final velocity of the train of three carts is: (Let all the carts collide and stick together at the same moment) a. 2.0 m/s b. 1.6 m/s C.-20 m/s d.-1.6 m/s ## Consider a system of three particles in the xy plane: m-1 kg at location (3, 0) m and has a velocity (3.5, 4) m/s, m2-3 kg at location (1,2.5) m and has a velocity (-2, 2) m/s and my 4 kg at location (0, -05) m and has a velocity (2, 1) m/s. Answer Q17 and Q18: Q17. Where is the center of mass of these objects (in m)? a. -0.75 i - 0.69 j Q18. The velocity of the center of mass in (m/s) is: a. 0.69 i +1.75 j C.-0.75 i+0.69j d. 0.75 i+0.69j b. 0.75 i-0.69 j c.-0.69 i -1.75 j d. 0.69 i-1.75j b. -0.69 i+ 1.75j ## In the Figure, the wheel rotate about the axle through O, taking a= 15.0 cm and b= 25.0 cm. Answer Q19, Q20 and Q21. Q19. Find the net torque on the wheel a. 5.95 N.m Q20. In the previous question, let the net torque on the wheel is 20 N.m, and if the moment of inertia of the wheel is 5 kg. m, the angular acceleration in rad/s' is: d. 535 N.m c. 4.15 N.m b. 3.85 N.m Q21. If the wheel rotate from the rest in question 20, the angular velocity of wheel in (rad/s) after 2 se a. 8 d.5 c.4 b. 2 a. 1 d. 10 c. 2 b. 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 2 4 12
Transcribed Image Text:Al kg block is attached to a Noring of force constant 300 N a in Figure The block is pulled 5 cm to the right of equilibriam and seleased from ret. Answer Q11 and Q12: Q11. The speed of the block as it passes through cquilibrium if the horinontal surface is frictionless: a. 0.87 m/s Q12. The speed of the block as it passes through equilitrium when the cocfficient of friction between block and surface is 0.4, a. 0,77 m/s b. 1.0 m/s e1.5 m/s 4.20 ms b. 0.88 m/s c.0.59 m/s d. 1.88 m/s Q13. The varying force depend on x is given by F(x) - (3x+2) N, where x in meter nd t ona body to move it from x-2m to x-3 m. The work done by this force on a body is: a. 72J b. 84J c. 603 Q14. The expression of Newton's second law is: a. EF = ma 4. 211 b. EP = c. Er = la d. All of them d. (a +b) Q15. A 2.0-kg ball with an initial velocity of 4i m/s collides with a wall and rebounds witha velocity of -4i m/s. What is the impulse exerted on the ball by the wall? a.-16iNs b. -12INS C. -18INS d.-24 INs Q16. Three carts of masses mi=4 kg, m2 -10 kg and my =3 kg move on a frictionless, horizontal track with spceds of vi=4 m/s to the right, V2 =3 m/s to the right, and vs -5 m/s to the left as shown in Figure. Velcro couplers make the carts stick together after colliding. The final velocity of the train of three carts is: (Let all the carts collide and stick together at the same moment) a. 2.0 m/s b. 1.6 m/s C.-20 m/s d.-1.6 m/s ## Consider a system of three particles in the xy plane: m-1 kg at location (3, 0) m and has a velocity (3.5, 4) m/s, m2-3 kg at location (1,2.5) m and has a velocity (-2, 2) m/s and my 4 kg at location (0, -05) m and has a velocity (2, 1) m/s. Answer Q17 and Q18: Q17. Where is the center of mass of these objects (in m)? a. -0.75 i - 0.69 j Q18. The velocity of the center of mass in (m/s) is: a. 0.69 i +1.75 j C.-0.75 i+0.69j d. 0.75 i+0.69j b. 0.75 i-0.69 j c.-0.69 i -1.75 j d. 0.69 i-1.75j b. -0.69 i+ 1.75j ## In the Figure, the wheel rotate about the axle through O, taking a= 15.0 cm and b= 25.0 cm. Answer Q19, Q20 and Q21. Q19. Find the net torque on the wheel a. 5.95 N.m Q20. In the previous question, let the net torque on the wheel is 20 N.m, and if the moment of inertia of the wheel is 5 kg. m, the angular acceleration in rad/s' is: d. 535 N.m c. 4.15 N.m b. 3.85 N.m Q21. If the wheel rotate from the rest in question 20, the angular velocity of wheel in (rad/s) after 2 se a. 8 d.5 c.4 b. 2 a. 1 d. 10 c. 2 b. 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 2 4 12
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