LA 3500 kg car moving on a flat, horizontal road turns a curve of 25 m radius. If the maximun speed the car can have to turn the curve successfuily is 10.3 m/s. find the coefficient of static friction (4,) between the tires and the road. a) 0.46 6 0.42 c) 0.57 d) 0.64 e) 0.51

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*Circle the best answer of the following: (0 +1)
1A 3500 kg car moving on a flat, horizontal roud turns a curve of 25 m radius. If the maximun speed
the car can have to turn the curve successfuily is 10.3 m/s. find the coefficient of static friction (H,)
between the tires and the road.
a) 0.46
2)
The only force acting on a 2 kg
object moving along the positive
x-axis is shown in the figure.. If the
kinetic energy of the abject at x-0,
m is 20 J, then it's kinetic energy (in
J) at x-7 m is equal to:
6 0.42
c) 0.57
d) 0.64
e) 0.51
10
a) 50
b) 42
c) 68
d) 56
62
3 Two forces F1 = (6i + 10) N and F2 = (-4i +6j) N acts on a 2 kg mass placed on a frictionless
horizontal surface. A third force F3 that must be added to move the mass with constant velocity of
(5i) m/s, is:
@ -2i-16j b) -51-2j c) 4j
(4 As a 4 kg object moves from (2i+5j) m to (-6i- 2j) m, the constant resultant force acting on it is equal
to (-4i- 6j) N, If the speed of the object at the initial position is 6 m/s, then its kinetic energy at its final
position is equal to:
a) 69 J
3 A force acting on an object moving along the x axis is given by F (12 x-3 x) N where x is in m. How
much work is done by this force as the object moves from x=-I m to x = +2 m?
a +9
d) -14j
e) -10i +4j
b) 37 J
O 146 J
d) 172 J
e) 32 J
b) +42
c) +28
d) -28
e) +11
Transcribed Image Text:*Circle the best answer of the following: (0 +1) 1A 3500 kg car moving on a flat, horizontal roud turns a curve of 25 m radius. If the maximun speed the car can have to turn the curve successfuily is 10.3 m/s. find the coefficient of static friction (H,) between the tires and the road. a) 0.46 2) The only force acting on a 2 kg object moving along the positive x-axis is shown in the figure.. If the kinetic energy of the abject at x-0, m is 20 J, then it's kinetic energy (in J) at x-7 m is equal to: 6 0.42 c) 0.57 d) 0.64 e) 0.51 10 a) 50 b) 42 c) 68 d) 56 62 3 Two forces F1 = (6i + 10) N and F2 = (-4i +6j) N acts on a 2 kg mass placed on a frictionless horizontal surface. A third force F3 that must be added to move the mass with constant velocity of (5i) m/s, is: @ -2i-16j b) -51-2j c) 4j (4 As a 4 kg object moves from (2i+5j) m to (-6i- 2j) m, the constant resultant force acting on it is equal to (-4i- 6j) N, If the speed of the object at the initial position is 6 m/s, then its kinetic energy at its final position is equal to: a) 69 J 3 A force acting on an object moving along the x axis is given by F (12 x-3 x) N where x is in m. How much work is done by this force as the object moves from x=-I m to x = +2 m? a +9 d) -14j e) -10i +4j b) 37 J O 146 J d) 172 J e) 32 J b) +42 c) +28 d) -28 e) +11
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